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SashulF [63]
2 years ago
6

Help meeeeeeeeeeeee its impossibleeeeee

Chemistry
2 answers:
melisa1 [442]2 years ago
7 0

Answer:

omg lol what even is this

fredd [130]2 years ago
6 0

Answer:

Nice! If only....

Explanation:

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D. To ensure the cooling process is not affected by surrounding temperature

Explanation:

The conical flask acts as a <u>t</u><u>e</u><u>m</u><u>p</u><u>e</u><u>r</u><u>a</u><u>t</u><u>u</u><u>r</u><u>e</u><u> </u><u>j</u><u>a</u><u>c</u><u>k</u><u>e</u><u>t</u><u>.</u>

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2 years ago
4 FeCO3 + O2 --&gt; 2 Fe2O3 + 4CO2
Andre45 [30]

The percentage yield of the reaction : 93.3%

Mass of FeCO₃ 2310.44 g

<h3>Further explanation </h3>

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Reaction

4 FeCO₃ + O₂ ⇒ 2 Fe₂O₃ + 4CO₂

MW FeCO₃ : 115,854 g/mol

MW Fe₂O₃ : 159,69 g/mol

  • mol FeCO₃

\tt \dfrac{35}{115.854}=0.302

  • mol Fe₂O₃

\tt \dfrac{2}{4}\times 0.302=0.151

  • mass Fe₂O₃

\tt 0.151\times 159.69=24.113~g

  • percent yield

\tt \dfrac{22.5}{24.113}\times 100\%=93.3\%

mol of 1 kg Fe₂O₃ = 1000 g

\tt \dfrac{1000}{159.69}=6.262

mol of FeCO₃

\tt \dfrac{4}{2}\times 6.262=12.524

mass of FeCO₃

\tt 12.524\times 115.854=1450.955~g

a purity of 62.8%

\tt \dfrac{100}{62.8} \times 1450.955=2310.44~g

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