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Deffense [45]
3 years ago
10

For a constant force, when the surface area is tripled the

Chemistry
1 answer:
IceJOKER [234]3 years ago
5 0

I think it is c

because it say tripled

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Why isn't geothermal energy used more often?
lianna [129]

Geothermal energy is not used more often because it's hard to find geothermal energy sources that are close to the surface (Option A).

<h3>What is Geothermal energy?</h3>

Geothermal energy is a special type of sustainable renewable source of clean energy that emerges from thermal (temperature) differences on the Earth, e.g., within geysers and similar geological formations.

In conclusion, geothermal energy is not used more often because it's hard to find geothermal energy sources that are close to the surface (Option A).

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5 0
2 years ago
If the pH of a solution is 5.4 then the concentration of H+ ions is ___|_x10^-6
Svetllana [295]
H is 4*10^6 M , OH is 2.5*10^-9 M
6 0
4 years ago
A solution is made by adding 35.5 mL of concentrated hydrochloric acid ( 37.3 wt% , density 1.19 g/mL1.19 g/mL ) to some water i
erastova [34]

Answer:

1.73 M

Explanation:

We must first obtain the concentration of the concentrated acid from the formula;

Co= 10pd/M

Where

Co= concentration of concentrated acid = (the unknown)

p= percentage concentration of concentrated acid= 37.3%

d= density of concentrated acid = 1.19 g/ml

M= Molar mass of the anhydrous acid

Molar mass of anhydrous HCl= 1 +35.5= 36.5 gmol-1

Substituting values;

Co= 10 × 37.3 × 1.19/36.5

Co= 443.87/36.6

Co= 12.16 M

We can now use the dilution formula

CoVo= CdVd

Where;

Co= concentration of concentrated acid= 12.16 M

Vo= volume of concentrated acid = 35.5 ml

Cd= concentration of dilute acid =(the unknown)

Vd= volume of dilute acid = 250ml

Substituting values and making Cd the subject of the formula;

Cd= CoVo/Vd

Cd= 12.16 × 35.5/250

Cd= 1.73 M

7 0
3 years ago
You have 7.86 x 10^23 molecules of NaCl. This would be equal to ___ grams of NaCl.
sergij07 [2.7K]

7.86 \times 10 {}^{23} atoms \\  \frac{7.86}{6.022}  \times  \frac{10 {}^{23} }{ {10}^{23} }   = 1.305\: moles

1.305 × (23+35.5) = 76.34 grams

3 0
3 years ago
What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?
____ [38]
Use the universal gas formula

PV=nRT
where
P=pressure ( 0.980 atm)
V=volume (L)
T=temperature ( 23 ° C = 23+273.15 = 296.15 ° K)
n=number of moles of ideal gas (0.485 mol)
R=universal gas constant = 0.08205 L atm / (mol·K)

Substitute values,
Volume, V (in litres)
=nRT/P
=0.485*0.08205*296.15/0.980
= 12.0256 L
= 12.0 L (to three significant figures)


Read more on Brainly.com - brainly.com/question/10606064#readmore
5 0
3 years ago
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