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In formation of a Type II Binary Compound, the metal atom present is<span>
NOT</span> found in either Group 1 or Group 2 on the periodic table. For the choices, Ba is under Group 2 on the periodic table, which makes it the atom not involved in formation of type II compounds. The answer is B.
Answer:
1.414 Moles
Solution:
Data Given:
Mass of MgS₂O₃ = 193 g
M.Mass of MgS₂O₃ = 136.43 g.mol⁻¹
Moles = ?
Formula Used:
Moles = Mass ÷ M.Mass
Putting values,
Moles = 193 g ÷ 136.43 g.mol⁻¹
Moles = 1.414 mol
The balanced net reactiion for the following half cells will be
Sn + Cr²⁺ ---> Sn²⁺ + Cr
<h3>What are
Half cells ?</h3>
A half cell is one of the two electrodes of an electrochemical cell.
An electrochemical cell comprises two half cells, where every half cell contains an electrode and an electrolyte.
A salt bridge or direct contact is needed to connect two half cells.
The balanced net reactiion for the given half cells will be
Sn + Cr²⁺ ---> Sn²⁺ + Cr
Learn more about Half cell here ;
brainly.com/question/1313684
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n = 1.5atm (15L) / .0821 (280k) = .98 mol NaCl
NaCl = 22.99g Na + 35.45g Cl = 58.44g NaCl
58.44g NaCl x .98 mol NaCl = 57.27g NaCl
Explanation:
hope you get it right :)
