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3 years ago

Which point is located on the x-axis

Mathematics

2 answers:

goblinko [34]3 years ago

4 0

Download connects works everytime

stiks02 [169]3 years ago

4 0

Answer:

Point C

Step-by-step explanation:

X axis is bottom row and Point C is directly on it.

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4. The cube root parent function is vertically stretched by a factor of 3, reflected in the x-axis,

Mademuasel [1]

Using translation concepts, it is found that the equation that represents the new function is:

$y = -3\sqrt[3]{x} - 8$

The cube root parent function is given by:

$y = \sqrt[3]{x}$

<h3>Translation:</h3>

The function goes through these following translations:

Vertically stretched by a factor of 3, that is, it is multiplied by 3, hence $y = 3\sqrt[3]{x}$ .

Reflected over the x-axis, that is, it is multiplied by -1, hence $y = -3\sqrt[3]{x}$ .

Translated 8 units down, that is, 8 is subtracted from the function, hence $y = -3\sqrt[3]{x} - 8$ .

Then, the equation is:

$y = -3\sqrt[3]{x} - 8$

To learn more about translation concepts, you can take a look at brainly.com/question/13671886

3 0

2 years ago

What is the image of the point (2, 8) after a rotation of 270 counterclockwise about the origin ?

jok3333 [9.3K]

Answer:

(8,-2)

Step-by-step explanation:

x and y switch places and x's sign is changed

6 0

3 years ago

Read 2 more answers

Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by

a_sh-v [17]

Answer:

Dimension of the box is $16.1\times 7.1\times 2.45$

The volume of the box is 280.05 in³.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is $L=21-2h$

The width of the box is $W=12-2h$

The volume of the box is $V=L\times W\times H$

$V=(21-2h)\times (12-2h)\times h$

$V=(21-2h)\times (12h-2h^2)$

$V=252h-42h^2-24h^2+4h^3$

$V=4h^3-66h^2+252h$

To maximize the volume we find derivative of volume and put it to zero.

$V'=12h^2-132h+252$

$0=12h^2-132h+252$

Solving by quadratic formula,

$h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}$

$h=\frac{132\pm72.99}{24}$

$h=2.45,8.54$

Now, substitute the value of h in the volume,

$V=4h^3-66h^2+252h$

When, h=2.45

$V=4(2.45)^3-66(2.45)^2+252(2.45)$

$V\approx 280.05$

When, h=8.54

$V=4(8.54)^3-66(8.54)^2+252(8.54)$

$V\approx -170.06$

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is $L=21-2(2.45)=16.1$

The width of the box is $W=12-2(2.45)=7.1$

So, Dimension of the box is $16.1\times 7.1\times 2.45$

6 0

4 years ago

The following two-way table describes student's

guajiro [1.7K]

P ( work/ senior ) = 0.14

The attached table

required

P ( work/ senior )

This is calculated using:

P ( work/ senior ) = n ( work/ senior )/ n ( senior ).

n ( work/ senior ) = 5

n ( senior ) = 25 + 5 + = 35

So:

P ( work/ senior ) = 5/35

P ( work/ senior ) = 0.14

Add 25+5+5 (because that is all the numbers in the 'Seniors' row) and then take the 5 that is in the 'Work' column and put that over 25. (5/25 fraction as a percent is 14).

Learn more about probability at

brainly.com/question/24756209

#SPJ4

7 0

2 years ago

If you rolled a fair number cube 1-6, 12 times, about how many times would you expect to roll a 5 or a 6?

Sav [38]

Well it is definately not c haha. I would say 3 because it is a pretty even chance of getting three.

4 0

3 years ago

Which point is located on the x-axis​

Which point is located on the x-axis