All categories

3 years ago

Study the Proof Given.

Mathematics

1 answer:

saul85 [17]3 years ago

7 0

2: Midpoint of segment AC is given as B3: Given4: Knowing that AC~=BC, AC~= DE

You might be interested in

What is 8 time the square root of 6

Helen [10]

Answer:

19.5959179423 or when simplified, 19.6

Step-by-step explanation:

3 0

3 years ago

The southward translation of the rose garden is along which axis? What integer represents a change of four yards south?

Sphinxa [80]

Going south means you're going in the negative direction along the y axis

Going 4 yards south would be represented as -4 on the y axis number line (this is the vertical number line)

3 0

3 years ago

3.75x = 3<br> how to do this, please help.

Travka [436]

Answer:

0.8

Step-by-step explanation:

you divide both sides by 3.75 (because its multiplied) so the 3.75 connected to the x cancels out and your left with x on the left and 3 over 3.75 equals 0.8 so its x = 0.8

3 0

3 years ago

Read 2 more answers

Plz help I’m getting timed

Fed [463]

id say its a rhombus. all the other shapes can have right angles

6 0

3 years ago

Read 2 more answers

$5 PAYPAL + BRAINLIEST TO ANSWER THS

expeople1 [14]

Answer:

Quadratic Equation:

$3x^2=2x +5$

$\text{Standard Form: } 3x^2-2x-5=0$

From the standard form of a Quadratic Function, we get:

$a=3,\:b=-2,\:c=-5$

Discriminant:

$\Delta=\left(-2\right)^2-4\cdot \:3\left(-5\right)$

$\Delta=\left(-2\right)^2+4\cdot \:3\cdot \:5$

$\Delta=64$

From the discriminant, we conclude that the equation will have two real solutions.

State that:

$b^2-4ac$

$b^2-4ac =0:\text{The equation has 1 real solution}$

$b^2-4ac >0:\text{The equation has 2 real solutions}$

By the way, solving the equation given:

$x=\frac{2\pm\sqrt{64}}{2\cdot \:3}$

$x=\frac{2\pm\sqrt{64}}{6}$

$x=\frac{2\pm8}{6}$

$x_{1} =\frac{10}{6}=\frac{5}{3}$

$x_{2}=\frac{-6}{6} =-1$

5 0

3 years ago