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anyanavicka [17]
3 years ago
13

PLEASE HELP!!! 30 POINTS

Mathematics
2 answers:
vladimir2022 [97]3 years ago
4 0

Answer:

True

12+7>9(2-3)-8

19> (-9)-8

19>-17

Step-by-step explanation:

worty [1.4K]3 years ago
4 0

Answer:

12+7=19 and 9(2-3)-8=-17

Step-by-step explanation:

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Find the quotient. Do not round. 55.328 ÷ 3.8 =<br> PLZ HELP NOW!!
Igoryamba
55.328 / 3.8 = 14.56
6 0
3 years ago
How many distinct triangles can be formed for which m∠A = 75°, a = 2, and b = 3?
antiseptic1488 [7]
We can use the Sine Law:a / sin A = b / sin B2 / sin 75° = 3 / sin B2 / 0.966 = 3 / sin B  ( after that we will cross multiply )
2 sin B = 3 · 0.9662 sin B = 2.898sin B = 2.898 : 2sin B = 1.499 > 1  ( it is not possible )Answer:  A ) No triangles can be formed.


8 0
3 years ago
Use the sample data and confidence level to construct the confidence interval estimate of the population proportion p. n equals
Alekssandra [29.7K]

Answer:

(0.767,0.833)

Step-by-step explanation:

The 95% confidence interval for population proportion p can be computed as

p-z_{\frac{\alpha }{2} } \sqrt{\frac{pq}{n} }

The z-value associated with 95% confidence level is 1.96.

whereas p=x/n

We are given that x=440 and n=550.

p=440/550=0.8

0.8-1.96\sqrt{\frac{0.8(0.2)}{550} }

0.8-1.96\sqrt{\frac{0.16}{550} }

0.8-1.96\sqrt{0.00029 }

0.8-1.96(0.01706)

0.8-0.03343

0.76657

Thus, the required confidence interval is

0.767<P<0.833  (rounded to 3 decimal places)

Hence, we are 95% confident that our true population proportion will lie in the interval (0.767,0.833)

3 0
3 years ago
A marble is randomly selected from a bag containing 15 black, 12 white, and 6 clear marbles. Find P(not clear). Round to the nea
dexar [7]
15+12+6= total number of marbles
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27 /33
.818181
82 percent
8 0
3 years ago
If a+b+c=0 then find the value of a^2+b^2+c^2/a^2-bc pls help me
VladimirAG [237]

a+b+c=0

[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]

[a^2+b^2+c^2+2ab+2ac+2bc=0]

[a^2+b^2+c^2=-(2ab+2ac+2bc)]

[a^2+b^2+c^2=-2(ab+ac+bc)] (i)

also

[a=-b-c]

[a^2=-ab-ac] (ii)

[-c=a+b]

[-bc=ab+b^2] (iii)

adding (ii) and (iii) ,we have

[a^2-bc=b^2-ac] (iv)

devide (i) by (iv)

[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
8 0
3 years ago
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