A circle is a curve sketched out by a point moving in a plane. If the distance from A to C is 6 units, then the distance from C to B is 6 units.
<h3>What is a circle?</h3>
A circle is a curve sketched out by a point moving in a plane so that its distance from a given point is constant; alternatively, it is the shape formed by all points in a plane that are at a set distance from a given point, the centre.
If the distance from A to C is 6 units, then the distance from C to B is 6 units. This is because AC and BC are the radii of the circle, therefore, both are equal to each other.
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Answer:
-1
Step-by-step explanation:
Arrange the numbers from least to greatest:
-17, -13, -11, -6, -1, 9, 14, 19, 19
Whichever number is in the middle is the median:
-1
Answer:
The next Step is
The Option is A
( 3x - 1 ) = ± 5
Step-by-step explanation:
Given:
![4(3x-1)^{2} - 17 = 83\\](https://tex.z-dn.net/?f=4%283x-1%29%5E%7B2%7D%20-%2017%20%3D%2083%5C%5C)
Solution:
Always while square rooting we get two values because square of negative number is also positive number.
Step wise:
![4(3x-1)^{2} - 17 = 83\\\\\\4(3x-1)^{2} = 100\\\\(3x-1)^{2}= 25\\\\\textrm{taking square rooting on both the side we get}\\\\(3x-1) =\pm\sqrt{25}\\\\\\(3x-1)=\pm5\\ \textrm{Which is the required step}\\\\3x=1 \pm5\\3x=6\ or\ 3x =-4\\\\x =2\ or\ x=\frac{-4}{3}](https://tex.z-dn.net/?f=4%283x-1%29%5E%7B2%7D%20-%2017%20%3D%2083%5C%5C%5C%5C%5C%5C4%283x-1%29%5E%7B2%7D%20%3D%20100%5C%5C%5C%5C%283x-1%29%5E%7B2%7D%3D%2025%5C%5C%5C%5C%5Ctextrm%7Btaking%20square%20rooting%20on%20both%20the%20side%20we%20get%7D%5C%5C%5C%5C%283x-1%29%20%3D%5Cpm%5Csqrt%7B25%7D%5C%5C%5C%5C%5C%5C%283x-1%29%3D%5Cpm5%5C%5C%20%5Ctextrm%7BWhich%20is%20the%20required%20step%7D%5C%5C%5C%5C3x%3D1%20%5Cpm5%5C%5C3x%3D6%5C%20or%5C%203x%20%3D-4%5C%5C%5C%5Cx%20%3D2%5C%20or%5C%20x%3D%5Cfrac%7B-4%7D%7B3%7D)
Answer:
![SA(x) = x^2 + \frac{12}{x}](https://tex.z-dn.net/?f=SA%28x%29%20%3D%20x%5E2%20%2B%20%5Cfrac%7B12%7D%7Bx%7D)
Step-by-step explanation:
Given
--- volume
![x \to base\ length](https://tex.z-dn.net/?f=x%20%5Cto%20base%5C%20length)
![y \to height](https://tex.z-dn.net/?f=y%20%5Cto%20height)
Required
The surface area as a function of base length
The volume (V) is calculated as:
![V = Base\ Area * Height](https://tex.z-dn.net/?f=V%20%3D%20Base%5C%20Area%20%2A%20Height)
![V = x*x*y](https://tex.z-dn.net/?f=V%20%3D%20x%2Ax%2Ay)
![V = x^2*y](https://tex.z-dn.net/?f=V%20%3D%20x%5E2%2Ay)
Make y the subject
![y = \frac{V}{x^2}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7BV%7D%7Bx%5E2%7D)
Substitute 3 for V
![y = \frac{3}{x^2}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B3%7D%7Bx%5E2%7D)
The surface area of the open box is:
![SA = x^2 + 2xy+2xy](https://tex.z-dn.net/?f=SA%20%3D%20x%5E2%20%2B%202xy%2B2xy)
![SA = x^2 + 4xy](https://tex.z-dn.net/?f=SA%20%3D%20x%5E2%20%2B%204xy)
Substitute: ![y = \frac{3}{x^2}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B3%7D%7Bx%5E2%7D)
![SA = x^2 + 4x*\frac{3}{x^2}](https://tex.z-dn.net/?f=SA%20%3D%20x%5E2%20%2B%204x%2A%5Cfrac%7B3%7D%7Bx%5E2%7D)
![SA = x^2 + 4*\frac{3}{x}](https://tex.z-dn.net/?f=SA%20%3D%20x%5E2%20%2B%204%2A%5Cfrac%7B3%7D%7Bx%7D)
![SA = x^2 + \frac{12}{x}](https://tex.z-dn.net/?f=SA%20%3D%20x%5E2%20%2B%20%5Cfrac%7B12%7D%7Bx%7D)
Hence, the function is:
![SA(x) = x^2 + \frac{12}{x}](https://tex.z-dn.net/?f=SA%28x%29%20%3D%20x%5E2%20%2B%20%5Cfrac%7B12%7D%7Bx%7D)
17 = B (16 cm by 24 cm)
18 = B (192)