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andriy [413]
2 years ago
10

Pls help me I’m failing lolz :)

Mathematics
1 answer:
kaheart [24]2 years ago
6 0
Answer: For no solution it would mean that there is no answer to the equation. For infinite solutions it would mean that any value for the variable would make the equation true.

Explanation: For example of no solution 6=5 as you can tell 6 is not the same to 5 so there is no solution. More examples are 2=3, 8=10, and 1=0. For infinite solutions examples are 2=2, 7=7, and 10=10 as we can see 2 does equal 2 and 7 equals 7 which makes it true and infinite.
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A certain article indicates that in a sample of 1,000 dog owners, 610 said that they take more pictures of their dog than of the
lbvjy [14]

Answer:

(a) The 90% confidence interval is: (0.60, 0.63) Correct interpretation is (3).

(b) The 95% confidence interval is: (0.42, 0.46) Correct interpretation is (1).

(c) First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).

Step-by-step explanation:

(a)

Let <em>X</em> = number of dog owners who take more pictures of their dog than of their significant others or friends.

Given:

<em>X</em> = 610

<em>n</em> = 1000

Confidence level = 90%

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

The sample proportion is:

\hat p=\frac{X}{n}=\frac{610}{1000}=0.61

The critical value of <em>z</em> for a 90% confidence level is:

z_{\alpha/2}=z_{0.10/2}=z_[0.05}=1.645

Construct a 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends as follows:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.61\pm 1.645\sqrt{\frac{0.61(1-0.61}{1000}}\\=0.61\pm 0.015\\=(0.595, 0.625)\\\approx(0.60, 0.63)

Thus, the 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends is (0.60, 0.63).

<u>Interpretation</u>:

There is a 90% chance that the true proportion of dog owners who take more pictures of their dog than of their significant others or friends falls within the interval (0.60, 0.63).

Correct option is (3).

(b)

Let <em>X</em> = number of dog owners who are more likely to complain to their dog than to a friend.

Given:

<em>X</em> = 440

<em>n</em> = 1000

Confidence level = 95%

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

The sample proportion is:

\hat p=\frac{X}{n}=\frac{440}{1000}=0.44

The critical value of <em>z</em> for a 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Construct a 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend as follows:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.44\pm 1.96\sqrt{\frac{0.44(1-0.44}{1000}}\\=0.44\pm 0.016\\=(0.424, 0.456)\\\approx(0.42, 0.46)

Thus, the 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend  is (0.42, 0.46).

<u>Interpretation</u>:

There is a 95% chance that the true proportion of dog owners who are more likely to complain to their dog than to a friend falls within the interval (0.42, 0.46).

Correct option is (1).

(c)

The confidence interval in part (b) is wider than the confidence interval in part (a).

The width of the interval is affected by:

  1. The confidence level
  2. Sample size
  3. Standard deviation.

The confidence level in part (b) is more than that in part (a).

Because of this the critical value of <em>z</em> in part (b) is more than that in part (a).

Also the margin of error in part (b) is 0.016 which is more than the margin of error in part (a), 0.015.

First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).

4 0
2 years ago
Hiiooo! Could someone please help me with this problem❤️❤️
Vera_Pavlovna [14]

Answer:

x=15

Step-by-step explanation:

divide 12/20 by 4 to get 3/5 then multiply by 3 to get your value of x

7 0
2 years ago
3x + 2y - (x + 1) + 5(2Y - 1)<br> Distributive Property
olga_2 [115]

Answer:

2x+12y

Step-by-step explanation:

1 is rounded out

7 0
3 years ago
Determine the intercepts of the line.<br> x-intercept:( , ) <br> y-intercept:( , )
Nastasia [14]

Answer:

x-intercept: (-7,0)

y-intercept: (0,2)

Step-by-step explanation:

The x-intercept is (-7,0) because on the graph we can see that the line lies on the x-axis on the point (-7,0).

The y-intercept is (0,2) because we can see that the line pass through the y-axis on the (0,2) point.

Hope this helps you :)

7 0
3 years ago
Read 2 more answers
How to convert 11/27 into a decimal
il63 [147K]

Answer:

11 ÷ 27 = 0.407407

Step-by-step explanation:

Una fracción, como 11/27, tiene un numerador y un denominador separado por una línea divisoria.

11 es el numerador, porque es el número de arriba de la línea divisoria.

27 es el denominador porque es el número de abajo de la línea divisoria.

Para convertir 11/27 a decimal, divide el numerador por el denominador.

4 0
3 years ago
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