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denpristay [2]
3 years ago
15

If the data below are represented by a comparative bar chart, the bar representing which of these will be the tallest? Passed Fa

iled Cats 24 26 Dogs 30 28
Mathematics
1 answer:
zhuklara [117]3 years ago
6 0

Answer:

  1. Left-handed Right-handed Boys 15 19 Girls 21 13 Right-handed girls
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What is the answer for C please help !! And explain
docker41 [41]
To determine the hypotenuse, use the formula a^2 + b^2 = c^2.

Place 80 as "a" and 39 as "b". Your formula should look like 80^2 + 39^2 = c^2.

Next, plug this into your calculator to get 7921. Then square root 7921.

Answer: 89
8 0
3 years ago
Help ehehehheheherhrurududud
Setler [38]

Answer:

99.8, 101.1, 106.3, 110.5

8 0
3 years ago
A 10 foot ladder is leaning against a wall. Call x the distance from the top of the ladder to the ground, and call y the distanc
liq [111]

-5.3\:\text{ft/s}

Step-by-step explanation:

We start by applying the Pythagorean theorem to the ladder, with its length L as the hypotenuse:

L^2 = 100\:\text{ft}^2 = x^2 + y^2

where x is the vertical distance from the top of the ladder to the ground and y is the horizontal distance from the bottom of the ladder to the wall. Taking the derivative of the above expression with respect to time, we get

0 = 2x\dfrac{dx}{dt} + 2y\dfrac{dy}{dt}

Solving for dx/dt, we get

\dfrac{dx}{dt} = -\left(\dfrac{y}{x}\right)\dfrac{dy}{dt} = -\left(\dfrac{\sqrt{L^2 - x^2}}{x}\right)\dfrac{dy}{dt}

We know that

\dfrac{dy}{dt} = 4\:\text{ft/s}

when x = 6 ft. So the rate at which the top of the ladder is going down is

\dfrac{dx}{dt} = -\left(\dfrac{\sqrt{100\:\text{ft}^2 - (6\:\text{ft})^2}}{6\:\text{ft}}\right)(4\:\text{ft/s})

\:\:\:\:\:\:\:= -5.3\:\text{ft/s}

The negative sign means that the distance x is decreasing as y is increasing.

5 0
3 years ago
1) a) Factorize: G(x) = (x+5)2 – 3x(x+5).
Arada [10]

Answer:

In bold.

Step-by-step explanation:

a.  (x+5)^2 – 3x(x+5)     x+5 is common

= (x + 5)(x + 5 - 3x)

= (x + 5)(5 - 2x)

b.  (x + 5)(5 - 2x) = 0

x = -5, 2.5.

2a.   Area of the square = (x + 5)^2

Area of triangle AEB

= 1/2 * base * height  

I am assuming that  H is the centre of AB , so

Area = x*x

= x^2.

2b

6x^2 = (x + 5)^2

6x^2 = x^2 + 10x + 25

5x^2 - 10x - 25 = 0

x^2 - 2x - 5 = 0

x = [-(-2) +/- sqrt(2^2 - 4*1*-5)] / 2

x = -1.45, 3.45.

 (we ignore the negative).

8 0
3 years ago
Explain how to estimate 586-321 two different ways
Olenka [21]
One way: estimate 586 to 600 and 321 to 300. Second way: estimate your answer
3 0
3 years ago
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