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ad-work [718]
3 years ago
11

How could you find out which weighs more a ton of pillows or a ton of bowling balls

Mathematics
1 answer:
4vir4ik [10]3 years ago
6 0

Answer:

You can put them on a scale and compare them.   Or you can figure out the weight of one individually.  A ton of pillows won't suddenly increase in weight compared to the bowling balls.

Step-by-step explanation:

MARK BRAINLEIST

PLSSSSSSS

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Step-by-step explanation:

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3 years ago
HELP!!
Liono4ka [1.6K]

Answer:

Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

Step-by-step explanation:

Part 1:

The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).

The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).

We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.

The relation between the vertices of ABCDE and MNOPQ are defined as

(x,y)\rightarrow (-x,y)

It means the polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2:

If polygon MNOPQ is translated 3 units right and 5 units down, then

(x,y)\rightarrow (x+3,y-5)

M(-2,8)\rightarrow V(-2+3,8-5)=V(1,3)

N(-4,12)\rightarrow W(-4+3,12-5)=W(-1,7)

O(-10,12)\rightarrow X(-10+3,12-5)=X(-7,7)

P(-8,8)\rightarrow Y(-8+3,8-5)=Y(-5,3)

Q(-6,6)\rightarrow Z(-6+3,6-5)=Z(-3,1)

Therefore the vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

6 0
3 years ago
Question 1.how to find simple interest
maria [59]

Answer:

answer for qn.1

Simple Interest Formulas and Calculations:

Use this simple interest calculator to find A, the Final Investment Value, using the simple interest formula: A = P(1 + rt) where P is the Principal amount of money to be invested at an Interest Rate R% per period for t Number of Time Periods.

7 0
4 years ago
One packet of biscuits requires 2 15/16 and 1 7/8 cups of sugar. Estimated total quantity of both ingredients used in 10 such pa
frez [133]

Answer:

<u>H</u><u>e</u><u>y</u><u> </u><u>M</u><u>a</u><u>t</u><u>e</u><u>!</u><u> </u><u>H</u><u>e</u><u>r</u><u>e</u><u>'</u><u>s</u><u> </u><u>y</u><u>o</u><u>u</u><u>r</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>.</u>

Step-by-step explanation:

<em><u>One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25</u></em>

<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32</u></em>

<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35</u></em>

<em><u>Total ingradiants for one packet of biscuits =</u></em>

<em><u>Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625</u></em>

<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =</u></em>

<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32</u></em>

Hope it helped you!

7 0
3 years ago
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