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valkas [14]
3 years ago
7

A visitor to a lighthouse wishes to determine the height of the tower. She ties a spool of thread to a small rock to make a simp

le pendulum, which she hangs down the center of a spiral staircase of the tower. The period of oscillation is 10.1 s. The acceleration of gravity is 9.8 m/s 2 . What is the height of the tower?
Physics
1 answer:
masha68 [24]3 years ago
5 0

To solve this problem we must rely on the equations of the simple harmonic movement that define the period as a function of length and gravity as

T = 2\pi \sqrt{\frac{l}{g}}

Where

l = Length

g = Gravity

Re-arrange to find L,

L = g (\frac{T}{2\pi})^2

Our values are given as

g = 9.81m/s

T = 10.1s

Replacing,

L = g (\frac{T}{2\pi})^2

L = (9.81) (\frac{10.1}{2\pi})^2

L = 25.348m

Therefore the height would be 25.348m

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