Simplify. pls pls pls helppp im really bad at math lol<br> a) 6 √3+ 4<br> b) 6 √6+ 3<br> c) 4 √3 + 6

Below is the graph of y= x.<br> Translate it to make it the graph of y=<br> x-1 + 4.

Oduvanchick [21]

First, to shift the graph of $y=x$ 1 unit to the right, so $y=x-1$
Second, to shift the graph of $y=x-1$ 4 units to the left, so $y=x-1+4$

<h2>Explanation:</h2>

To translate the graph of a function is part of Rigid Transformations because the basic shape of the graph is unchanged

$Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:$

$\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c$

$\bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)$

In this case, we have the graph of:

$y=x$

And we need to translate it to make it the graph of:

$y=x-1+4$

According to our rules we need:

First, to shift the graph of $y=x$ 1 unit to the right, so $y=x-1$
Second, to shift the graph of $y=x-1$ 4 units to the left, so $y=x-1+4$

But $y=x-1+4$ is the same as $y=x+3$ , so the previous steps can be simplified as:

Shifting the graph of $y=x$ 3 unit to the left.

Below are shown those graphs:

The blue one is $y=x$
The red one is $y=x-1+4$

<h2>Learn more:</h2>

Shifting graphs: brainly.com/question/10010217

#LearnWithBrainly

6 0

3 years ago

Round 2.794 to the tenths place

viva [34]

2.8

The tenths place is right after the decimal, so when we round 2.794 to the nearest tenths place, we get 2.8

Hope this helps! Have a good day :)

8 0

2 years ago

The sum of the first three terms of an arithmetic sequence is 108, and the sum of the next three terms is 183. what is the value

qaws [65]

The key is to find the first term a(1) and the difference d.

in an arithmetic sequence, the nth term is the first term +(n-1)d
the firs three terms: a(1), a(1)+d, a(1)+2d
the next three terms: a(1)+3d, a(1)+4d, a(1)+5d,
a(1) + a(1)+d +a(1)+2d=108
a(1)+3d + a(1)+4d + a(1)+5d=183

subtract the first equation from the second equation: 9d=75, d=75/9=25/3
Plug d=25/3 in the first equation to find a(1): a(1)=83/3

the 11th term is: a(1)+(25/3)(11-1)=83/3 +250/3=111

Please double check my calculation. <span />

4 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST!!!

ExtremeBDS [4]

I think they are called sides.

6 0

2 years ago

Plz help im desperate plzzzzzz

IrinaK [193]

Answer: D

Step-by-step explanation:

8 0