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kumpel [21]
2 years ago
13

Calculate: Press Reset. Start with 1.900 × 10 24(or 19.00 × 10 23 ) molecules of Cu2O. A. Calculate the number of moles: B. Use

the Gizmo to verify your calculation. Were you correct? C. Is the method for converting molecules to moles the same as that for atoms?
Chemistry
1 answer:
asambeis [7]2 years ago
7 0

Answer:

1.661 mol.

Explanation:

Hello!

In this case, since the Avogadro's number allows us to relate the number of formula units in one mole of the substance; we need to keep in mind that elements are related by atoms and compounds by molecules, it means:

1 mol = 6.022x10^{23}atoms\\\\1 mol = 6.022x10^{23}molecules

Thus, for copper (I) oxide, we compute the moles, given the atoms as shown below:

n = 1.900x10^{24}molecules*\frac{1mol}{ 6.022x10^{23}molecules} \\\\n = 1.661mol

Thus, the method we use is the same.

Best regards

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Lithium diorganocopper (Gilman) reagents are prepared by treatment of an organolithium compound with copper(I) iodide. Decide wh
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Answer:

See explanation and image attached

Explanation:

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7 0
2 years ago
What concentrations of acetic acid (pKa = 4.76) and acetate would be required to prepare a 0.15 M buffer solution at pH 5.0? Not
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Answer:

Acetic acid 0,055M and acetate 0,095M.

Explanation:

It is possible to prepare a 0,15M buffer of acetic acid/acetate at pH 5,0 using Henderson-Hasselblach formula, thus:

pH = pka + log₁₀ [A⁻]/[HA] <em>-Where A⁻ is acetate ion and HA is acetic acid-</em>

Replacing:

5,0 = 4,76 + log₁₀ [A⁻]/[HA]

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As concentration of buffer is 0,15M, it is possible to write:

<em>[A⁻] + [HA] = 0,15M </em><em>(2)</em>

Replacing (1) in (2):

1,7378[HA] + [HA] = 0,15M

2,7378[HA] = 0,15M

[HA] = 0,055M

Thus, [A⁻] = 0,095M

That means you need <em>acetic acid 0,055M</em> and <em>acetate 0,095M</em> to obtain the buffer you need.

i hope it helps!

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3 years ago
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Answer:

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