Question

Based on the activity series provided, which reactants will form products? f > cl > br > i cui2 br2 right arrow. cl2 alf3 right arrow. br2 nacl right arrow. cuf2 i2

Answer 1

The reactants that will form products will be $2CuI_2 + Br2$.

Activity series

Elements at higher positions in the activity series will be able to displace those in lower positions in solutions.

Thus:

$2CuI_2 + Br2 --- > 2CuBr +2 I_2$ because Br is higher than I in the activity series.

Cl cannot displace F in $Cl2 + AlF_3$ because F is higher than Cl in the activity series.

Also, Cl is higher than Br in the activity series, thus, the reaction $Br_2 + NaCl$ cannot form products.

I cannot displace F, thus, $CuF_2 + I_2$ cannot form products.

More on activity series can be found here: brainly.com/question/13934381

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