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sattari [20]
3 years ago
8

Students are studying how two substances react. The students mix substance 1 with substance 2 in a solution. Later the students

boil the solution, releasing substance 1 as a gas and leaving substance 2 as a solid. What type of change is described in the paragraph above? How do you know?
This is a chemical change, because the two substances were mixed together.


This is a chemical change, because the two substances were separated chemically by boiling.


This is a physical change, because the two substances were separated physically by boiling.


This is a chemical change, because a gas was released.
Chemistry
1 answer:
Mashutka [201]3 years ago
4 0

This is a chemical change, because a gas was released.

One of the substances must have evolved the gas and changed into something else (a chemical change).

Mixing two substances and separating them by boiling are <em>physical changes</em>.

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Answer:

i = 2.483

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For electrolytes:

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Where:

Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)

4.5701g of MgCl₂ are:

4.5701g ₓ (1mol / 95.211g) = 0.048000 moles

43.238g of water are:

43.238g ₓ (1mol / 18.015g) = 2.400 moles

Replacing in (1):

0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm

0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)

2.4mol + i*0.048mol = 2.4mol / 0.9527

2.4mol + i*0.048mol = 2.5192mol

i*0.048mol = 2.5192mol - 2.4mol

i = 0.1192mol / 0.048mol

<em>i = 2.483</em>

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I hope it helps!

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