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sattari [20]
3 years ago
8

Students are studying how two substances react. The students mix substance 1 with substance 2 in a solution. Later the students

boil the solution, releasing substance 1 as a gas and leaving substance 2 as a solid. What type of change is described in the paragraph above? How do you know?
This is a chemical change, because the two substances were mixed together.


This is a chemical change, because the two substances were separated chemically by boiling.


This is a physical change, because the two substances were separated physically by boiling.


This is a chemical change, because a gas was released.
Chemistry
1 answer:
Mashutka [201]3 years ago
4 0

This is a chemical change, because a gas was released.

One of the substances must have evolved the gas and changed into something else (a chemical change).

Mixing two substances and separating them by boiling are <em>physical changes</em>.

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2) shape of the molecule to conclude whether there is a net dipole momentum.

You already, likely, know that the electronegativities of H and O are significatively different, being O more electronegative thatn H. So, you can conclude easilty that the electrons are atracted more by O than by H, thus creating two dipoles H→O

Regarding the shape, it may appear that the molecule is symmetrical, which would lead to the cancellation of the two dipoles. But that is not the true. The H2O2 is not symmetrical.

The lewis structure just show this shape

      **   **
H - O - O - H
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which is what may induce to think that the molecule is symmetrical, leading to the misconception that it is nonpolar.

But in a three dimensional arrangement you could see that the hydrogens are placed in non symmetrical positions, which leads to the formation of a net dipole momentum, and thus to a polar molecule.

The fact that H2O2 is a polar compound is the reason why it can be mixed with water and the H2O2 that you buy in the pharmacy is normally a solution in water.

So, the hydrogen peroxide is polar because the hydrogens are not placed symmetrically in the molecule, which result in a net dipole momentum.
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