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pickupchik [31]
2 years ago
9

Which is not a particle within an atom

Chemistry
2 answers:
Colt1911 [192]2 years ago
7 0
An ion is not a particle within the atoms
Korolek [52]2 years ago
5 0

Answer:

Ion.

Explanation:

Ions are not a particle within an atom.

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Below are 5 sets of potential solutes for you to compare. Both members of each pair are very soluble in water. If you had equal
Gelneren [198K]

Answer:

Option D. AlCl₃, MgC₂

Explanation:

We need to dissociate all the salts, to determine the i. (Van't Hoff factor).

The salt who has the highest value, will be the better conductor of electricity

CsCl  → Cs⁺  +  Cl⁻   i = 2

CaCl → Ca²⁺ +  Cl⁻   i = 2

CaS → Ca²⁺ +  S⁻²    i = 2

Li₂S → 2Li⁺  +  S⁻²    i = 3

KBr →  K⁺  +  Br⁻       i = 2

AlCl₃ →  Al³⁺ + 3Cl⁻   i = 4

MgC₂  →  Mg²⁺  +  2C⁻   i = 3

KI  →  K⁺  +  I⁻     i = 2

K₂S  →  2K⁺  + S⁻²   i = 3

The biggest i, is in pair D.

6 0
3 years ago
Which answer is a scientifically accurate description of velocity?
agasfer [191]

Answer:

B. The motorcyclist traveled southeast along a highway at 55 mph and reached the campsite in less than the two-hour estimated time.

Explanation:

<em>Velocity </em>is the rate at which an object changes position in a specific direction. It has both <em>magnitude and direction.</em>

Travelling <em>southeast</em> at <em>55 mph</em> is a <em>velocity</em>. It gives both speed and direction.

Statements A., B., and C. give the direction but not the speed.

3 0
3 years ago
Read 2 more answers
If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi
zlopas [31]

Answer:

T_{eq}=28.9\°C

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

Q_{Cd}+Q_{W}=0

Thus, we insert mass, specific heat and temperatures to obtain:

m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}

Now, we plug in to obtain:

T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

Best regards!

6 0
2 years ago
Turbines are 100 percent efficient. True False
max2010maxim [7]
False because there’s only 60% turbulence 20% heat 20% sound
6 0
3 years ago
Read 2 more answers
142Pm &gt; 142 Nd +<br> what is the answer to this equation
erastova [34]

Explanation:

nnbbnmkmknn bnnnbbtbbbbn' nn' t

4 0
2 years ago
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