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Evgesh-ka [11]
3 years ago
7

PLEASE HELP 20 POINTS

Mathematics
1 answer:
Doss [256]3 years ago
8 0

Answer:

1) squares and rectangles

2) squares and rhombuses

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HELP ME ASAP WILL MARK BRAINLIEST
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1912

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1) Solve 12.5 +8= 27.<br> What does s=
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112.324 nearest tenth
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The area of a trapezoid is 69.6 in2 and its altitude is 8.7 in. Find the perimeter of the trapezoid if the sum of its legs is eq
BaLLatris [955]
1. To solve this problem, you must apply the formula for calculate the area of the trapezoid, which is:
 
 A=(B+b)h/2
 
 A is the area of the trapezoid (A=69.6 in²).
 (B+b) is the sum of the bases of the trapezoid.
 h is the height of the trapezoid (h=8.7 in).
 
 2. When you clear the sum of the bases (B+b), you have:
 
 A=(B+b)h/2
 2A=<span>(B+b)h
</span><span> (B+b)=2A/h
</span> (B+b)=2(69.6 in²)/(8.7 in)
 (B+b)=16 in
 
 3. The problem says that <span>the sum of its legs is equal to the sum of its bases, therefore, the perimeter is:
</span> 
 Sum of the legs=Sum of the bases (B+b)=16 in
 
 Perimeter=16 in+16 in
 Perimeter=32 in
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