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2 years ago

I really need help some one please

Mathematics

1 answer:

Alika [10]2 years ago

7 0

The factorization of A is y = (x - 8)(x + 7).
The factorization of B is y = (x + 1)(x - 4)(x - 5)

In order to find these, you must first find where each graph crosses the x-axis. In the first problem it does so at 8 and -7. In order to find the correct parenthesis for those, you need to write it out as a statement and then solve for 0.

x = 8 ---> subtract 8 from both sides
x - 8 = 0
This means we use (x - 8) in our factorization.

You then need to repeat the process until you have all the pieces. In the second problem, there will be 3 instead of 2 since it crosses the axis 3 times.

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Answer:

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Step-by-step explanation:

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2 years ago

Find the area of the composite figure in terms of the figure (use 3.14 for pi)

svp [43]

Answer:

105.12 ft²

Step-by-step explanation:

Let's first find the area of the rectangle.

$10\cdot8=80$ ft², so the rectangle has an area of 80ft².

To find the area of the semi-circle, we find the area of a whole circle and divide by two.

The formula to find the area of a circle is $\pi r^2$ . The radius is 4, as the diameter is 8.

$3.14\cdot4^2$

$3.14\cdot16$

$50.24\div2=25.12$

Add 80 and 25.12:

$80+25.12=105.12$

Hope this helped!

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2 years ago

What does it mean when someone says “ your nobody to lie to”?

timurjin [86]

Answer: You're not important basically

Step-by-step explanation:

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1 year ago

What is the value of x?

deff fn [24]

The value of x is the variable of the number it is closer to

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3 years ago

Katie wants to create a rectangular frame for a picture. She has 60 inches of material. If she wants the length to be 3 more tha

Fofino [41]

Answer:

Largest possible length is <em>21 inches</em>.

Step-by-step explanation:

Given:

Total material available = 60 inches

Length to be 3 more than twice of width.

To find:

Largest possible length = ?

Solution:

As it is rectangular shaped frame.

Let length = $l$ inches and

Width = $w$ inches

As per given condition:

$l = 2w+3$ ..... (1)

Total frame available = 60 inches.

i.e. it will be the perimeter of the rectangle.

Formula for perimeter of rectangle is given as:

$P = 2 \times (Width + Length)$

Putting the given values and conditions as per equation (1):

$60 = 2 \times (w+ l)\\\Rightarrow 60 = 2 \times (w+ 2w+3)\\\Rightarrow 60 = 2 \times (3w+3)\\\Rightarrow 30 = 3w+3\\\Rightarrow 3w = 27\\\Rightarrow w = 9 \ inch$

Putting in equation (1):

$l = 2\times 9+3\\\Rightarrow l = 21\ inch$

So, the answer is:

Largest possible length is <em>21 inches</em>.

6 0

2 years ago