Answer:
1
Step-by-step explanation:
HOW TF IS THAT A HARD QUESTION
See examples before for the method to solving literal equations for a given variable: Solve A = bh for b. Since h is multiplied times b, you must divide both sides by h in order to isolate b. Since (c+d) is divided by 2, you must first multiply both sides of the equation by 2.
There are 59 integer solutions
Such questions are best solved by writing cases and calculating the total number of cases. So beginning with
1) x = -3. The possible combinations are as follows:-
-3 2 13
-3 3 12
-3 4 11
-3 5 10
-3 6 9
-3 7 8
-3 8 7
-3 9 6
-3 10 5
-3 11 4
10 combinations
2) x = -2
-2 2 12
through
-2 11 3
10 combinations
3) x = -1
-1 2 11
through
-1 10 3
9 combinations
4) x = 0
0 2 10
through
0 9 3
8 combinations
as we can see from the pattern at x =1 we get 7 combinations, at x =2 we get 6 combinations, at x=3 we get 5 combinations and at x =4 we get 5 combinations.
Thus total number of combinations 4+5+6+7+8+9+10+10 = 59 integer solution.
Learn more about combinations here :
brainly.com/question/13387529
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Answer:
Suppose we have a polynomial of degree N with a leading coefficient A and roots {x₁, x₂, ..., xₙ}
We can write this polynomial as:
P(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)
such that the terms:
(x - x₁), (x - x₂), etc...
are called the factors.
In this case, we know that the roots OF THE FACTORS
are:
(x = - 2)
(x = - (1 + √5))
(x = + 3i)
If the root of the polynomial is x = -2, then the factor should be:
(x + 2)
which is zero when we evaluate x in -2
Then the correct option is the first one.
