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2 years ago

Can you guys help me with this? I really need help.

Mathematics

1 answer:

dmitriy555 [2]2 years ago

5 0

Answer:

Uhh haahah Hindi ko alam yan

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Justin wants to use 188 ft of fencing to fence off the greatest possible rectangular area for a garden. What dimensions should h

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Letter C is your answer.

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3 years ago

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Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

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1 year ago

What is the radius of the following circle?

lara [203]

Answer:

The radius is: $2\sqrt{3}$

Step-by-step explanation:

The equation of a circle in center-radius form is:

$(x - h)^2 + (y - k)^2 = r^2$

Where the center is at the point (h, k) and the radius is "r".

So, given the equation of the circle:

$x^2+y^2=12$

You can identify that:

$r^2=12$

Then, solving for "r", you get that the radius of this circle is:

$r=\sqrt{12}\\\\r=2\sqrt{3}$

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3 years ago

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6x44<br> hbgvtfwtydtwftdftwyfdywdwd

Ipatiy [6.2K]

Answer:

264

Step-by-step explanation:

well you could have just used a calculator!

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2 years ago

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The length of a rectangular garden is 3 yd less than twice its length. The perimeter of the garden is 78 yd. What are the width

Alenkasestr [34]

Complete question :

Answer:

Width = 14 yards ; length = 25 yards

Step-by-step explanation:

Given that :

The length of a rectangular garden is 3 yd less than twice its length. The perimeter of the garden is 78 yd. What are the width and length of the garden?

Width of garden (W) = w

Lenght of garden (L) = 2w - 3

Perimeter of a rectangle : 2 (L + W)

2(2w - 3 + w) = 78

2(3w - 3) = 78

6w - 6 = 78

6w = 78 + 6

6w = 84

w = 14 yards

Length = 2(14) - 3

Length = 28 - 3 = 25 yards

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2 years ago