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gavmur [86]
3 years ago
11

Expression A: 4x + 5 Expression B: 2 + 4x + 3 Which statement can be used to show that these expressions are equivalent?

Mathematics
1 answer:
Alexandra [31]3 years ago
3 0

Answer:

Step-by-step explanation:

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lana is putting a lace trim arount the border of a circular tablecloth. the tablecloth has a diameter of 1.2 meters. to the near
Inessa [10]

Answer:

4m

Step-by-step explanation:

We are looking for the circumference

We need to find the radius

r = d/2 = 1.2/2 = .6

C = 2*pi*r

C = 2*pi*(.6)

C = 1.2*pi

We can approximate pi by 3.14

C =1.2*3.14

C =3.768 m

To the nearest meter

C = 4m

8 0
3 years ago
6.1.7 (Video Solution) An article in Human Factors (June 1989) presented data on visual accommodation (a function of eye movemen
horsena [70]

Answer:

- the sample mean is 44

- the sample standard deviation is 12.35

Step-by-step explanation:

given information:

data, x_{i} = 36.45, 67.90, 38.77, 42.18, 26.72, 50.77, 39.0, 50.23

the number of data, n = 8

the sample mean, xbar

xbar = ∑x_{i}/n

       = (36.45+67.90+38.77+42.18+26.72+50.77+39.0+50.23)/8

       = 352.08/8

       = 44

standard deviation, s

s = \sqrt{sum(x_{i} - xbar)^{2}/n-1}

  = \sqrt{(36.45-44)^{2}+(36.45-44)^{2}.........(39.00-44)^{2}+(50.23-44)^{2}/(8-1 )}

 = \sqrt{\frac{1067.12}{7} }

 = 12.35

7 0
3 years ago
Answer!!!!!Please!!!!Will do anything!!!
Marizza181 [45]
I think it is the first one

hope this helps
3 0
3 years ago
Read 2 more answers
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft 6 in tall, and the initial velocity of the ball is 40 f
weqwewe [10]

Answer:

t = 0.293 s and 14.52 s

Step-by-step explanation:

The heights of the ball in feet is given by the equation as follows :

S = -2.7t^2+40t+6.5

Where t is the number of seconds after the ball was thrown.

We need to find is the ball 18 ft above the moon's surface.

Put S = 18 ft

-2.7t^2+40t+6.5=18\\\\-2.7t^2+40t=18-6.5\\\\-2.7t^2+40t-11.5=0

It is a quadratic equation. Its solution is given by :

t=\dfrac{-40+\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)},\dfrac{-40-\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)}\\\\t=0.293\ s,14.52\ s

So, the ball is at first 0.293 s and then 14.52 s above the Moon's surface.

8 0
3 years ago
What is the GCF of 14 and 21
n200080 [17]
Hey there the answer is, 

<span>The Greates Common Factor (GCF) is:   7
</span>

Hope I helped!!!<3

8 0
3 years ago
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