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Musya8 [376]
3 years ago
15

Write an equation, in the slope intercept form, of the line with an x-intercept at (3 , 0) and a y-intercept at (0 , -5).

Mathematics
1 answer:
mamaluj [8]3 years ago
6 0

Hello : let  A(3,0)    B(0,-5)<span>
the slope is :   (YB - YA)/(XB -XA)
(-5-0)/(0-3)  = 5/3
</span>

<span> an equation, in the slope intercept form is : y - (-5) = (5/3)(x-0)
y = (5/3)x - 5</span>
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A school made $880 from ticket sales for the school play. From the ticket sales, $250 were from adult tickets.
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Answer:

126 Students

Step-by-step explanation:

First, you subtract the money from the adult tickets from the total ($880), that leaves $630.

Since each student ticket is $5, you divide $630 by 5, which equals 126.

So, 126 students attended.

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Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the
igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:  

Steps

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Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

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2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

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3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

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Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

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Mean of difference = 7.5/10

Mean of difference = 0.75

Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

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8pi ft

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