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3 years ago

Write an equation, in the slope intercept form, of the line with an x-intercept at (3 , 0) and a y-intercept at (0 , -5).

Mathematics

1 answer:

mamaluj [8]3 years ago

6 0

Hello : let A(3,0) B(0,-5)<span>
the slope is : (YB - YA)/(XB -XA)
(-5-0)/(0-3) = 5/3
</span>

<span> an equation, in the slope intercept form is : y - (-5) = (5/3)(x-0)
y = (5/3)x - 5</span>

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The area of a square floor on a scale drawing is 100 sq cm, and the scale of the drawing is 1cm:2ft. What is the area of the act

likoan [24]

Square root of 100 = 10 cm. Next, 10*2 = 20^2 = 400 ft. Next, convert cm into ft, which would make 100 into about 3.3 ft. The ratio would then be about 3/400. Does that help?

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3 years ago

"Mia jogs 3 kilometers in 20 minutes. There are about 0.6 miles in a kilometer. What is Mia’s approximate speed in miles per min

Lapatulllka [165]

First we need to find Mia's speed (v) in km/min

v = distance travelled/ time
v = 3 km/20 minutes
v = 0.15 km /min

in order to convert the speed into mile/min, we need to use the conversion factor given in which for every kilometer, there is 0.6 miles.

v = 0.15 km/min *(0.6 miles/ km)
v =0.09 miles/min

therefore the speed in miles/min is 0.09 miles/min

4 0

3 years ago

Read 2 more answers

In ΔABC (m∠C = 90°), the points D and E are the points where the angle bisectors of ∠A and ∠B intersect respectively sides BC an

Airida [17]

This is a little long, but it gets you there.

ΔEBH ≅ ΔEBC . . . . HA theorem
EH ≅ EC . . . . . . . . . CPCTC
∠ECH ≅ ∠EHC . . . base angles of isosceles ΔEHC
ΔAHE ~ ΔDGB ~ ΔACB . . . . AA similarity
∠AEH ≅ ∠ABC . . . corresponding angles of similar triangle
∠AEH = ∠ECH + ∠EHC = 2∠ECH . . . external angle is equal to the sum of opposite internal angles (of ΔECH)
ΔDAC ≅ ΔDAG . . . HA theorem
DC ≅ DG . . . . . . . . . CPCTC
∠DCG ≅ ∠DGC . . . base angles of isosceles ΔDGC
∠BDG ≅ ∠BAC . . . .corresponding angles of similar triangles
∠BDG = ∠DCG + ∠DGC = 2∠DCG . . . external angle is equal to the sum of opposite internal angles (of ΔDCG)
∠BAC + ∠ACB + ∠ABC = 180° . . . . sum of angles of a triangle
(∠BAC)/2 + (∠ACB)/2 + (∠ABC)/2 = 90° . . . . division property of equality (divide equation of 12 by 2)
∠DCG + 45° + ∠ECH = 90° . . . . substitute (∠BAC)/2 = (∠BDG)/2 = ∠DCG (from 10 and 11); substitute (∠ABC)/2 = (∠AEH)/2 = ∠ECH (from 5 and 6)
This equation represents the sum of angles at point C: ∠DCG + ∠HCG + ∠ECH = 90°, ∴ ∠HCG = 45° . . . . subtraction property of equality, transitive property of equality. (Subtract ∠DCG+∠ECH from both equations (14 and 15).)

5 0

3 years ago

The ratio of men to women in a movie theater is 3:5. As two more men and one more woman walk in, the ratio of men to women becom

34kurt

Answer:

C. 20

Step-by-step explanation:

Let's say M is the original number of men and W is the original number of women.

M / W = 3 / 5

(M+2) / (W+1) = 2 / 3

Let's cross multiply both equations:

5M = 3W

3(M+2) = 2(W+1)

Let's simplify the second equation:

3M + 6 = 2W + 2

3M + 4 = 2W

From the first equation:

M = 3/5 W

Substitute:

3 (3/5 W) + 4 = 2W

9/5 W + 4 = 2W

4 = 1/5 W

W = 20

There were originally 20 women.

Let's check our answer. That would mean that M = 3/5 W = 12.

After 2 men walk in and 1 woman, W = 21 and M = 14, so 14/21 = 2/3. Looks like the answer is correct!

Answer C.

7 0

3 years ago

Please help!!!

marusya05 [52]

Answer:

the answer is B.FALSE

Step-by-step explanation:

hope it helps

5 0

2 years ago