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3 years ago

11

What is the least common denominator for 1/2 & 2/3 ?

1 answer:

IrinaVladis [17]3 years ago

4 0

Answer: 6

Step-by-step explanation:

1/2 = 3/6

2/3 = 4/6

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3 years ago

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Mark owns Siberian Husky sled dogs. He knows from data collected over the years that the weight of the dogs is a normal distribu

kozerog [31]

Calculate the z-score for the given data points in the item using the equation,

z-score = (x - μ) / σ

where x is the data point, μ is the mean, and σ is the standard deviation.

Substituting,
(47.7) z-score = (47.7 - 52.5)/2.4 = -2

This translates to a percentile of 2.28%.

(54.9) z-score = (54.9 - 52.5)/2.4 = 1

This translates to a percentile of 84.13%.

Then, subtract the calculate percentiles to give us the final answer of <em>81.85%.</em>

Thus, 81.85% of the Siberian Husky sled dogs are expected to weigh between 47.7 and 54.9 lbs.

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3 years ago

Which of the following is the correct factorization of the polynomial below? x^3-15

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3 years ago

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Yanka [14]

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3 years ago

Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.

SashulF [63]

<u>ANSWER</u>

${r}^{2} = 4 \cos2\theta$

<u>EXPLANATION</u>

The Cartesian equation is

${( {x}^{2} + {y}^{2} )}^{2} = 4( {x}^{2} - {y}^{2} )$

We substitute

$x = r \cos( \theta)$

$y = r \sin( \theta)$

and

${x}^{2} + {y}^{2} = {r}^{2}$

This implies that

${( {r}^{2} )}^{2} = 4(( { r \cos\theta) }^{2} - {(r \sin\theta) }^{2} )$

Let us evaluate the exponents to get:

${r}^{4} = 4({ {r}^{2} \cos^{2}\theta } - {r}^{2} \sin^{2}\theta)$

Factor the RHS to get:

${r}^{4} = 4{r}^{2} ({ \cos^{2}\theta } - \sin^{2}\theta)$

Divide through by r²

${r}^{2} = 4 ({ \cos^{2}\theta } - \sin^{2}\theta)$

Apply the double angle identity

$\cos^{2}\theta -\sin^{2}\theta= \cos(2 \theta)$

The polar equation then becomes:

${r}^{2} = 4 \cos2\theta$

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3 years ago