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Liula [17]
4 years ago
11

What is the least common denominator for 1/2 & 2/3 ?

Mathematics
1 answer:
IrinaVladis [17]4 years ago
4 0

Answer: 6

Step-by-step explanation:

1/2 = 3/6

2/3 = 4/6

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A regular octagon has a perimeter of 48 cm. What is the length of each side?
Anarel [89]

Answer:

Each side of the octagon a length of 6 cm

Step-by-step explanation:

Divide the perimeter by the amount of sides the shape has.

48 ÷ 8 = 6

4 0
3 years ago
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i am a 2 dimensional shape that has four sides. I have four 90 degree angles.i have two sets of parallel lines. i also have two
Roman55 [17]
The answer is 190 for u'r information
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5. Write down the nth term of each of the following G.Ps
yawa3891 [41]

Answer:

1i) nth term = 12(-b/4)^(n-1)

ii) nth term = 3(-1/9)^(n-1)

2i) Sixth term= (-3b^5)/256

ii) Eight term = -1/1594323

Question:

The complete question as found on brainly (question-10746111):

Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.

i) 12,-3b,......sixth term

ii) 3,-1/3,..........;8th term?

Step-by-step explanation:

1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.

i) 12,-3b,......;sixth term

1st term = a= 12

r = common ratio = 2nd term /1st term

r = -3b/12 = -b/4

Then we would find the nth term

See attachment for details

ii) 3,-1/3,..........;8th term

1st term = a= 3

r = common ratio = 2nd term /1st term

r = (-⅓)/3 = (-⅓)(⅓) = -1/9

Then we would find the nth term

See attachment for details

2) we are to determine the sixth term in (i) and eight term in (ii)

See attachment for details

Sixth term= (-3b^5)/256

Eight term = -1/1594323

7 0
3 years ago
The perimeter of an equilateral triangle is 21cm, find its length
Margarita [4]

Answer:

7cm is the length for each side of an equalateral triangle

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3 years ago
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X2 + y2 - 14x + 10y + 65 = 0 <br><br> will lie ENTIRELY in Quadrant
Afina-wow [57]
Rearranging to standard form 
= (x - 7)^2 + (y + 5)^2 = -65 + 49 + 25
 (x-7)^2 + (y+5)^2 = 9 
so the centre is at (7,-5) and the radius is 3

so the circle will be entirely in Quadrant 4.
5 0
3 years ago
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