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Effectus [21]
2 years ago
13

The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of

RT and R1, what is R2 R2 blank is ohms
Mathematics
1 answer:
ivanzaharov [21]2 years ago
3 0
<h2>Answer:</h2>

R_2  is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors R_1 and R_2 connected together in parallel, the total resistance R_T is given by;

\frac{1}{R_T} = \frac{1}{R_1}  + \frac{1}{R_2}              ---------(i)

<em>Make </em>R_2<em> subject of the formula;</em>

=> \frac{1}{R_2} = \frac{1}{R_T}  - \frac{1}{R_1}  

=> \frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}

=>   {R_2} = \frac{R_TR_1}{R_1 - R_T}       ---------------(ii)

From the question,

R_1 = 6Ω

R_T = 2Ω

Substitute these values into equation (ii) as follows;

=> {R_2} = \frac{2*6}{6 - 2}

{R_2} = \frac{12}{4}

R_2 = 3Ω

Therefore, the value of R_2 = 3 ohms or R_2 = 3Ω

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elena55 [62]
There is a 6% decrease as 639.20 divided 680 is 0.94. Meaning 6% decrease.
6 0
2 years ago
What is the value of M/3=2
katrin [286]

Answer:

M=3*2

M=6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Darren wants to estimate the mean age in a population of trees. He'll sample nnn trees and build a 90\%90%90, percent confidence
Alchen [17]

Using the z-distribution, as we have the standard deviation for the population, it is found that the smallest sample size required to obtain the desired margin of error is of 77.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

The margin of error is given by:

M = z\frac{\sigma}{\sqrt{n}}

In this problem, we have that the parameters are given as follows:

M = 3, z = 1.645, \sigma = 16.

Hence, solving for n, we find the sample size.

M = z\frac{\sigma}{\sqrt{n}}

3 = 1.645\frac{16}{\sqrt{n}}

3\sqrt{n} = 1.645 \times 16

\sqrt{n} = \frac{1.645 \times 16}{3}

(\sqrt{n})^2 = \left(\frac{1.645 \times 16}{3}\right)^2

n = 76.97

Rounding up, the smallest sample size required to obtain the desired margin of error is of 77.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
1 year ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided
noname [10]

Given:

The points are M(6,16) and Z(-1,14).

To find:

The distance between given points.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

So, the distance between two points M(6,16) and Z(-1,14) is

d=\sqrt{(-1-6)^2+(14-16)^2}

d=\sqrt{(-7)^2+(-2)^2}

d=\sqrt{49+4}

d=\sqrt{53}

d=7.28011

d\approx 7.3

Therefore, the distance between given points is 7.3 units.

8 0
2 years ago
Señora Cruz will use four triangles on the door decor. How many square centimeters of paper will Señora Cruz use to create the t
mafiozo [28]

Answer:

  50.32 cm²

Step-by-step explanation:

The area of a triangle can be computed using the formula ...

  A = 1/2bh

For a triangle with base 3.7 cm and height 6.8 cm, the area is ...

  A = 1/2(3.7 cm)(6.8 cm) = 12.58 cm²

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For four (4) triangles, Señora Cruz will need 4 times this area:

  4 × (12.58 cm²) = 50.32 cm²

Señora Cruz will need 50.32 cm² of paper to create her door decor.

4 0
2 years ago
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