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SOVA2 [1]
2 years ago
13

What is the weight per cookie for cheesecake

Mathematics
1 answer:
SpyIntel [72]2 years ago
5 0

Answer:

full question

Step-by-step explanation:

full question

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Amanda, Rafael, and Michael served a total of 92 orders Monday at the school cafeteria. Rafael served 2 times as many orders as
Schach [20]

The number of orders Michael, Rafael and Amanda served are 16.8, 33.6, and 41.6 servings

respectively.

<h3>Equation</h3>

  • Michael = x
  • Rafael = 2x
  • Amanda = 2x + 8
  • Total servings = 92 orders

x + 2x + (2x + 8) = 92

3x + 2x + 8 = 92

5x = 92 - 8

5x = 84

x = 84/5

x = 16.8 servings

Therefore,

Michael = x

= 16.8 servings

Rafael = 2x

= 2(16.8)

= 33.6 servings

Amanda = 2x + 8

= 33.6 + 8

= 41.6 servings

Learn more about equation:

brainly.com/question/4344214

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5 0
2 years ago
The sum of eleven and a number is negative nine.
Misha Larkins [42]

Answer:

The sum is 2. ...........

8 0
2 years ago
Read 2 more answers
Find the value of x.<br> 48°<br> (7x + 13)
Pavel [41]

Answer:

336x + 624

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Determine the 20th term of the sequence: -14,-8, -2, 4, 10,
Pie

Answer: The 20th term is 100

Step-by-step explanation: It adds by 6 each time

-14, -8, -2, 4, 10, 16, 22, 28, 34, 40, 46, 52, 58, 64, 70, 76, 82, 88, 94, 100

3 0
3 years ago
Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul
Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of  Jack in z   =F₁z=90.5 N in direction (+z)

Force of  Jill  in x     = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of  Jill  in y     =F₂y=-82.3*sin45°=   + 58.19 N (+y)

Force of  Jane  in x  =F₃x=125*cos45°=   + 88.4 N (+x)

Force of  Jane  in y   =F₃y=125*sin45°=   + 88.4  N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N  (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2}   }

F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2}   }

F_{n} = 174.9 N

7 0
3 years ago
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