What is the weight per cookie for cheesecake

Your monthly living expenses are $585.00. Your monthly fixed expenses are $1078.00. Your annual fixed expenses are $2700.00. Cal

abruzzese [7]

The answer for the total monthly expenses: $1078.80 + $585.00 = 1663.0

8 0

3 years ago

Which is greater least or equal to

katen-ka-za [31]

Answer:

< (less than)

Step-by-step explanation:

One ninth would be less than one seventh because you would have to cut let's say a circle into more pieces, making each piece smaller.

(first image is 1/9, second image is 1/7)

7 0

3 years ago

X squared+6x+5 what is this factorise

NISA [10]

Well, your question is basically;
x²+6x+5
   Well first you have to find two numbers that when added will give you +6 and when multiplied will give you 5. Well, in this case, the numbers are; (+1 and +5). So you add them to the equation. So;
x²+1x+5x+5
Hope you noticed that 6x was removed. Anyway;
   You have to put the equation in two brackets with two terms in each
(x²+1x)+(5x+5)
   Next, you bring out what is commom in each bracket and use it to divide what is in the bracket
x(x+1)+5(x+1)
   Now you notice that the two things in the bracket are the same. They have to be.
Next, you put the terms outside the bracket together and choose one of the terms in a bracket. So;
(x+5) (x+1)
   So the equation factorised is (x+5) (x+1). But if you want to go ahead to find x, then you can say;
(x+5) (x+1)
x+5=0 x+1=0
Take the +5 over Take the +1 over the equal to, where it becomes -1. So;
the equal sign where x=-1
it becomes -5. So;
x=-5 OR x=-1
   By the way, here's a little secret, the answers are always the opposite of the two numbers chosen at the beginning(+1 and +5). Hope i helped. If you have any more problems, let me know.

4 0

3 years ago

What is the probability of you picking a weekend day from the days of the week?

svet-max [94.6K]

Answer:

3/7

Step-by-step explanation:

its 3/7 because there are 3 weekend days and there are 7 days in total in one week, so out of the week there is 3 weekend days.

i hope this helps :)

6 0

3 years ago

A certain article indicates that in a sample of 1,000 dog owners, 610 said that they take more pictures of their dog than of the

lbvjy [14]

Answer:

(a) The 90% confidence interval is: (0.60, 0.63) Correct interpretation is (3).

(b) The 95% confidence interval is: (0.42, 0.46) Correct interpretation is (1).

(c) First, the confidence level in part(b) is more than the confidence level in part(a) is, so the critical value of part(b) is more than the critical value of part(a), Second the margin of error in part(b) is more than than in part(a).

Step-by-step explanation:

(a)

Let X = number of dog owners who take more pictures of their dog than of their significant others or friends.

Given:

X = 610

n = 1000

Confidence level = 90%

The (1 - α)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The sample proportion is:

$\hat p=\frac{X}{n}=\frac{610}{1000}=0.61$

The critical value of z for a 90% confidence level is:

$z_{\alpha/2}=z_{0.10/2}=z_[0.05}=1.645$

Construct a 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends as follows:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.61\pm 1.645\sqrt{\frac{0.61(1-0.61}{1000}}\\=0.61\pm 0.015\\=(0.595, 0.625)\\\approx(0.60, 0.63)$

Thus, the 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends is (0.60, 0.63).

Interpretation:

There is a 90% chance that the true proportion of dog owners who take more pictures of their dog than of their significant others or friends falls within the interval (0.60, 0.63).

Correct option is (3).

(b)

Let X = number of dog owners who are more likely to complain to their dog than to a friend.

Given:

X = 440

n = 1000

Confidence level = 95%

The (1 - α)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The sample proportion is:

$\hat p=\frac{X}{n}=\frac{440}{1000}=0.44$

The critical value of z for a 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Construct a 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend as follows:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.44\pm 1.96\sqrt{\frac{0.44(1-0.44}{1000}}\\=0.44\pm 0.016\\=(0.424, 0.456)\\\approx(0.42, 0.46)$

Thus, the 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend is (0.42, 0.46).

Interpretation:

There is a 95% chance that the true proportion of dog owners who are more likely to complain to their dog than to a friend falls within the interval (0.42, 0.46).

Correct option is (1).

(c)

The confidence interval in part (b) is wider than the confidence interval in part (a).

The width of the interval is affected by:

The confidence level
Sample size
Standard deviation.

The confidence level in part (b) is more than that in part (a).

Because of this the critical value of z in part (b) is more than that in part (a).

Also the margin of error in part (b) is 0.016 which is more than the margin of error in part (a), 0.015.

First, the confidence level in part(b) is more than the confidence level in part(a) is, so the critical value of part(b) is more than the critical value of part(a), Second the margin of error in part(b) is more than than in part(a).

4 0

3 years ago