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Naily [24]
3 years ago
9

Enter an equivalent fraction 2/13​

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
7 0

Answer:

4/26

Step-by-step explanation:

pretty simple ngl

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Which is bigger, 4/3 or 4/4
velikii [3]

Answer:

4/3

Step-by-step explanation:

This is just one of the ways you can do it

find the decimal or divide each fraction

so for the first one 4/3

4 divide by 3 is 1.33333

while 4 divide by 4 is 1

Compare

1.333333 and 1

Of course, 1.33333 is bigger than 1

so 4/3 is the correct answer

Hope this helps :)

4 0
3 years ago
Read 2 more answers
Identify the slope and y-intercept of a graph of the equation y=1/2x-5
ehidna [41]

Answer:

Slope: 1/2

y-intercept: -5

(✿◠‿◠)

7 0
3 years ago
PLEASE HELP ASAP DUE RN!
yKpoI14uk [10]

Answer:

27.9

Step-by-step explanation:

i googled it for you

7 0
3 years ago
5m + 3 ( 8m +7 ) +4^2<br><br> Can someone help me
Pie

Answer:

29m+37?

Step-by-step explanation:

<em>Pemdas</em>

5m+3(8m+7)+4^2

Parentheses first: 5m+24m+21+4^2

Exponents next: 5m+24m+21+16

No multiplication or division so addition is last:

29m+37

These two can't add together because one has a variable.

7 0
3 years ago
A lumber company is making boards that are 2920.0 millimeters tall. If the boards are too long they must be trimmed, and if the
Effectus [21]

Answer:

The value of the test statistic is of 0.22.

Step-by-step explanation:

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected mean, \sigma is the standard deviation(square root of the variance) and n is the size of the sample.

A lumber company is making boards that are 2920.0 millimeters tall.

This means that \mu = 2920.

A sample of 12 is made, and it is found that they have a mean of 2922.7 millimeters with a variance of 121.00.

This means that X = 2922.7, n = 12, \sigma = \sqrt{121} = 11. So

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{2922.7 - 2922}{\frac{11}{\sqrt{12}}}

t = 0.22

The value of the test statistic is of 0.22.

4 0
3 years ago
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