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defon
3 years ago
10

A cell phone provider charges $30 each month to have a cell on their plan, but their talk and text are not free. It costs $0.05

for every minute of talk and $0.10 for every text sent. There is no charge for receiving texts. a. Write an algebraic expression that represents the monthly costs of the plan, given t represents the number of minutes and x represents the number of texts sent for each month.
Mathematics
2 answers:
Alenkasestr [34]3 years ago
8 0

Answer:$30m+.05t+.10x

Ugo [173]3 years ago
7 0
The answer is 10x +0.05x +30=y
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3 years ago
Given csc(A) = 60/16 and that angle A is in Quadrant I, find the exact value of sec A in simplest radical form using a rational
Katarina [22]

Answer:

\displaystyle \sec A=\frac{65}{63}

Step-by-step explanation:

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\displaystyle \csc A=\frac{65}{16}

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How do you find the height of a triangle?
Dmitrij [34]
Answers:  height, "h", of a triangle:    <span> h = 2A /  (b₁ + b₂) .
___________________________________________________ </span>
Explanation:
__________________________________________________
The area of a triangle, "A", is equal to (1/2) * (b₁ + b₂) * h ; 
                                    or:  A = (1/2) * (b₁ + b₂) * h
                                    or: write as:  A =  [(b₁ + b₂) * h] / 2 ;
          ___________________________________________
                                     in which:  A = area of the triangle; 
                                                       b₁ = length of one of the bases
                                                                 of the triangle ("base 1");
                                                       b₂ = length of the other base
                                                                 of the triangle ("base 2");
                                                       h = height of the triangle;
____________________________________________________
To find the height of the triangle, we rearrange the formula to solve for "h" (height); assuming that all the units are the same (e.g. feet, centimeters); if no "units" are given, then the assumption is that the units are all the same.
We can use the term "units" if desired, in such cases; in which the area, "A" is measured in "square units"; or "units²",
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So, given our formula for the "Area, "A"; of a triangle:
_________________________________________________
 A =  [(b₁ + b₂) * h] / 2 ; we solve for "h" in terms of the other values; by isolating "h" (height) on one side of the equation.
     If we knew the other values; we plug in the those other values.
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  Given:   A =  [(b₁ + b₂) * h] / 2 ;

Multiply EACH side of the equation by "2" ;
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            2*A = {  [(b₁ + b₂) * h] / 2 } * 2 ;
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to get:
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           2A = (b₁ + b₂) * h ;
_____________________________________________________
           Now, divide EACH side of the equation by:  "(b₁ + b₂)" ;  to isolate "h"
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            2A /  (b₁ + b₂) = [ (b₁ + b₂) * h ] / (b₁ + b₂);
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to get:
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           2A /  (b₁ + b₂)  =  h ;  ↔<span>  h = 2A /  (b₁ + b₂)  .
__________________________________________________</span>
7 0
3 years ago
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