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defon
3 years ago
10

A cell phone provider charges $30 each month to have a cell on their plan, but their talk and text are not free. It costs $0.05

for every minute of talk and $0.10 for every text sent. There is no charge for receiving texts. a. Write an algebraic expression that represents the monthly costs of the plan, given t represents the number of minutes and x represents the number of texts sent for each month.
Mathematics
2 answers:
Alenkasestr [34]3 years ago
8 0

Answer:$30m+.05t+.10x

Ugo [173]3 years ago
7 0
The answer is 10x +0.05x +30=y
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76

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4(-4(-9)-17)

4(36-17)

4(19)

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She earned 150 in interest
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15y^2-15y+2y+7-2y^2+4
scoray [572]

Answer:

13 y^2 - 13 y + 11

Step-by-step explanation:

Simplify the following:

15 y^2 - 2 y^2 + 2 y - 15 y + 4 + 7

Grouping like terms, 15 y^2 - 2 y^2 + 2 y - 15 y + 4 + 7 = (15 y^2 - 2 y^2) + (-15 y + 2 y) + (7 + 4):

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Answer: 13 y^2 - 13 y + 11

8 0
3 years ago
Jack, walker, and trust have $100 altogether. Jack has $20 more than Walker. Trust has $14 more than walker. How much money does
nekit [7.7K]

Answer: Jack has $42

Step-by-step explanation:

Let be "j" the amount of money in dollars that Jack has, "w"  the amount of money in dollars that Walker has and "t"  the amount of money in dollars that Trust has.

You know that they have $100 altogether, then you can write the following equation:

j+w+t=100   [Equation 1]

Jack has $20 more than Walker, then:

j=w+20      [Equation 2]

And  Trust has $14 more than walker, then you can write this equation:

t=w+14      [Equation 3]

Substitute the  Equation 2 and the  Equation 2 into the first one:

j+w+t=100\\\\(w+20)+w+(w+14)=100

Now, solve fo "w":

w+20+w+w+14=100\\\\3w+34=100\\\\3w=100-34\\\\w=\frac{66}{3}\\\\w=22

Finally, substiute the value of "w" into the Equation 2 and evaluate:

j=w+20\\\\j=22+20\\\\j=42

7 0
3 years ago
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