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alexandr402 [8]
3 years ago
13

I need help answering this Chemestry question!

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
5 0

Answer:

c (the thrid option)

Explanation:

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What mass of oxygen forms from 71.89 g CO2?
liubo4ka [24]

Answer:

52.28g

Explanation:

Given:

Mass of CO₂ = 71.89g

Solution:

The equation of the reaction:

                  CO₂ → C + O₂

We want to determine the mass of O₂ that will form from this reaction.

To do this, find the number of moles of CO₂:

   Number of moles of CO₂ = \frac{mass}{molar mass}

Molar mass of CO₂ = 12+ 2(16) = 44g/mol

   Number of moles of CO₂ = \frac{71.89}{44} = 1.63mole

From the equation of the reaction:

      1mole of CO₂ will produce 1 mole of O₂

 So 1.63 mole of CO₂ also produces 1.63mole of O₂

The mass of O₂:

    Mass of O₂ = number of moles of O₂ x molar mass of O₂

Molar mass of O₂ = 2 x 16 = 32g/mol

    Mass of O₂ = 1.63 x 32 = 52.28g

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What is the compound SCI2
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What are the exceptions to the periodic trends in ionization energy?
Verdich [7]

Answer:

The exceptions to the periodic trends in ionization energy are the first ionization energy of beryllium is higher than that of boron and the first ionization energy of nitrogen is also higher than that of oxygen.

Explanation:

Taking a close look at the figure of first ionization energies, it clearly shows that the first ionization energy of beryllium is higher than that of boron and the first ionization energy of nitrogen is also higher than that of oxygen.

This is as a result of Hund's rule and electron configuration. For example,  the first ionization potential electron of beryllium is obtained from a 2s orbital while that of boron comes from a 2p electron. However, for oxygen and nitrogen, their electrons are obtained from 2p orbitals. While spin is uniform for all 2p electrons of nitrogen, it is different for oxygen.

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