Mass = 5.90 x 114 = 672.6g.
This can be rounded to <em>673g</em>
<em>C = 12 grams x 8 = 96 grams </em>
<em>H = 1 gram x 18 = 18 grams </em>
<em>Total = 96 + 18 = 114 grams in one mole. </em>
<u>If you have 5.9 moles, multiply this by the weight of one mole (114 grams) = 672.6 rounded to 673 grams in 5.9 moles. </u>
D.) Atoms are always in motion
Answer:
THE MOLAR MASS OF XCL2 IS 400 g/mol
THE MOLAR MASS OF YCL2 IS 250 g/mol.
Explanation:
We calculate the molar mass of XCL2 and YCL2 by bringing to mind the formula for molar mass when mass and amount or number of moles of the substance is given.
Number of moles = mass / molar mass
Molar mass = mass / number of moles.
For XCL2,
mass = 100 g
number of mole = 0.25 mol
So therefore, molar mass = mass / number of moles
Molar mass = 100 g / 0.25 mol
Molar mass = 400 g/mol.
For YCL2,
mass = 125 g
number of mole = 0.50 mol
Molar mass = 125 g / 0.50 mol
Molar mass = 250 g/mol.
So therefore, the molar mass of XCL2 and YCL2 IS 400 g/mol and 250 g/mol respectively.
I believe the answer to this is A.
Answer:
The temperature is 42.5 °C
Explanation:
We apply the Law of Ideal Gases to solve this:
P . V = n . R . T
First, we convert the bar into atm, so we make a rule of three.
1.013 bar is 1 atm
1.3 bar is (1.3 . 1) /1.013 = 1.28 atm
1.28atm . 15L = n . 0.082 . T
We must convert the mass to moles ( mass / molar mass)
20 g / 30 g / mol = 0.666 moles
1.28atm . 15L = 0.666 mol . 0.082 . T
(1.28 atm . 15L) / (0.666 mol . 0.082) = T
315.5 K = T
As this is absolute temperature we must convert to °C
315.5 K - 273= 42.5 °C
