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exis [7]
2 years ago
7

The director of special events for Sun City believed that the amount of money spent on fireworks displays for the Fourth of July

was predictive of attendance at the Fall Festival held in October. She gathered the following data to test her suspicion.
4th of July ($000) Fall Festival (000)
10.6 8.8
8.5 6.4
12.5 10.8
9.0 10.2
5.5 6.0
12.0 11.1
8.0 7.5
7.5 8.4
9.0 9.5
10.0 9.8
7.5 6.6
10.0 10.1
6.0 6.1
12.0 11.3
10.5 8.8
1. Determine the regression equation
2. Complete the ANOVA table.
Mathematics
1 answer:
vazorg [7]2 years ago
3 0

Tgwre is no attached ANOVA chart.

Answer:

y = 0.762x + 1.72

Step-by-step explanation:

Given the data above , the regression model obtained using a Pearson linear regression calculator is :

y = 0.762x + 1.72

The regression equation cloud be interpreted as follows :

Slope, which is the increase in the value of y per unit increase in x = 0.762

The intercwpt, which is the value of x when y = 0 is 1.72

x = amount of money spent in fireworks for 4th July

y = Attendance at the October fall festival.

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inysia [295]

Answer 10:

<em>X </em>= (5,0)

Answer 11:

<em>AB</em> = 11.18

Answer 12:

<em>N/A</em>

Step-by-step explanation:

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3 years ago
What is the LCD of 6, 9, &amp; 12?
mina [271]

6 = 6/1

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3 years ago
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erma4kov [3.2K]

Answer:

1:94 2:-94

Step-by-step explanation:

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8 0
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An ice-cream truck sells milkshakes for $3.50 and cones for $2. On Wednesday, a total of 45 milkshakes and cones were sold, and
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Answer:

247.5

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3 years ago
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KatRina [158]
Hi there!

First, scientific notation is when you take a number like 15,000 or 0.0015 and turn it into a number that is less than 10 and greater than 1. What you do to make it that is you move that decimal point over to the left or right as needed. So for example, 15,000 would be 1.5 × 10^{4} and 0.0015 is 1.5 × 10^{-3}.

So if one light year is 5.88 × 10^{12} mi. that is just the scientific notation for 5880000000000 mi.

So if you take 5880000000000 mi. and multiply it by 11 then you get 64680000000000

5880000000000 × 11 = 64680000000000 or 6.468 × 10^{13}

So the answer would be \boxed{64680000000000} or \boxed{6.468*10^{13} }

Your friend, ASIAX
5 0
3 years ago
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