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never [62]
2 years ago
6

Choose the representations or descriptions that model the relation provided in each item. For each relation, select all situatio

ns that apply. x -2 0 2 4 f(x) 4 0 4 16 The relation is a function. f( x) = -2 x f(4)= -2 domain: {-2, 0, 2, 4} The relation is not a function. f( x) = x2
Mathematics
1 answer:
Pie2 years ago
8 0

Answer:

It is B and D because it is the only one that matches the input and outputs. D shows a perfect graph of the points while B shows the points themselves. They cannot be a linear function since they are not linear so it is not E or F.

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Please help!! need to pass this class!!
Bezzdna [24]

Answer:

ADB and DBC

Step-by-step explanation:

Angles ADB and DBC are both marked with three curved lines which shows that their angles are congruent to each other.

Hope this helps! :)

3 0
2 years ago
Can anyone help?! Will mark brainliest!
IRINA_888 [86]

Answer:

Volume are over 120-177 because the layers are communicate each factors and angles..

Step-by-step explanation:

both 6 have 3 factors

A are for equation

5 centimeters are not allowed to communicate with other lessons and Numerator numbers...

HOPE IT HELPS!!

4 0
3 years ago
A computer programming team has 17 members. (a) How many ways can a group of nine be chosen to work on a project? As in Example
Natali5045456 [20]

The number of groups that can be chosen from the team of 17 depends on the given conditions of the selection.

The correct responses are;

(a) The number of ways of choosing groups of 9 from the 17 members are 24,310 ways.

(b) (i) The number of groups of 9 containing 5 women and 4 men are 8,820 groups.

(ii) The number of groups of 9 that contain at least one man is 24,309 groups.

(iii) The number of groups of 9 that contain at most 3 women are 2,649 groups.

(c) If two team members refuse to work together on projects, the number of groups of 9 that can be chosen are 17,875 groups.

(d) If two team members must work together or not at all the number of groups of 9 that can be chosen are 1,430 groups.

Given,

The combination of n objects taking r at a time is given as follows

ₙCr = (ⁿr)

(a) The number of ways of choosing groups of 9 from the 17 members is given as follows;

Number of ways of choosing groups of 9 = (17, 9)  = 24,310 ways.

(b) (i) Number of women = 9

Number of men = 8

Number of groups of 9 containing 5 women and 4 men = (9, 5) x (8, 4)

(9, 5) x (8, 4) = 126 x 70 = 8820

Number of groups of 9 containing 5 women and 4 men = 8,820 groups.

(ii) The number of groups that contain at least one man is (17, 9) - (9, 9)

(17, 9) - (9, 9) = 24,310 - 1 = 24,309

The number of groups that contain at least one man are 24,309 groups.

(iii) The number of groups of 9 that contain at most 3 women if given as follows;

(8, 8) × (9, 1) + (8, 7) × (9, 2) + (8, 6) × (9, 3) = 2649

The number of groups of 9 that contain at most 3 women are 2,649 groups.

(c) Given that two team members refuse to work together on projects, the number of groups of 9 that can be chosen are (15, 9) + 2 × (15, 8)

(15, 9) + 2 × (15, 8) = 5,005 + 2 × 6,435 = 17,875

(d) Two team members must work together or not at all is (15, 7) - (15, 9)

(15, 7) - (15, 9) = 6,435 - 5,005 = 1,430

The number of groups of 9 that can be chosen two team members must work together or not at all are 1,430 groups.

Learn more about number of ways here;

brainly.com/question/25310371

#SPJ4

7 0
1 year ago
I don’t understand about this question
Alja [10]

Answer:

Domain

Step-by-step explanation:

7 0
2 years ago
Add. (3b + 5) + (2b + 4)
zaharov [31]

Answer:

\huge{ \fbox{ \sf{5b + 9}}}

Step-by-step explanation:

\star{ \text{( \: 3b + 5) + (2b + 4)}}

\text{Step \: 1 \:  :  \sf{Remove \: the \: unnecessary \: parentheses}}

\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}

\text{That \: means, \: the \: expression \: remains \: the \: same. \: Just \: you \: have \: to \: remove \: the \: parentheses.}

\mapsto{ \sf{3b + 5 + 2b + 4}}

\text{Step \: 2 \:  : Collect \: like \: terms.}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}

\mapsto{ \sf{3b + 2b + 5 + 4}}

\mapsto{ \sf{5b + 5 + 4}}

\text{ Step \: 3 \:  :  \sf{Add \: the \: numbers : 5 \: and \: 4}}

\mapsto{ \boxed {\sf{ {5b + 9}}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

4 0
3 years ago
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