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3 years ago

6

Choose the representations or descriptions that model the relation provided in each item. For each relation, select all situatio

ns that apply. x -2 0 2 4 f(x) 4 0 4 16 The relation is a function. f( x) = -2 x f(4)= -2 domain: {-2, 0, 2, 4} The relation is not a function. f( x) = x2

1 answer:

Pie3 years ago

8 0

Answer:

It is B and D because it is the only one that matches the input and outputs. D shows a perfect graph of the points while B shows the points themselves. They cannot be a linear function since they are not linear so it is not E or F.

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A cable service provider charges $40 per month for its basic package plus an additional $5.35 for each premium channel chosen. T

lakkis [162]

40/x represents the amount payed per month

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3 years ago

Read 2 more answers

If total revenue is 3000,cost of goods is $1500, and a total selling expensesis $500; what is the profit for business?

tekilochka [14]

This sounds like simple addition & subtraction.
Total revenue = $3,000
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Total expenses = $500
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6 0

3 years ago

Match the numerical expressions to their simplest forms.

Aloiza [94]

Answer:

$(a^6b^1^2)^\frac{1}{3}$ = $a^2b^4$

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$ = $a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$ = $a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$ = $ab^3$

Step-by-step explanation:

Simplify each of the expressions:

1

$(a^6b^1^2)^\frac{1}{3}$

Distribute the exponent. Multiply the exponent of the term outside of the parenthesis by the exponents of the variable.

$(a^6b^1^2)^\frac{1}{3}$

$a^6^*^\frac{1}{3}b^1^2^*^\frac{1}{3}$

Simplify,

$a^2b^4$

2

Use a similar technique to solve this problem. Remember, a fractional exponent is the same as a radical, if the denominator is (2), then the operation is taking the square root of the number.

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$

Rewrite as square roots:

$\frac{\sqrt{a^5b^3}}{\sqrt{(ab)}^-^1}$

A negative exponent indicates one needs to take the reciprocal of the number. Apply this here:

$\frac{\sqrt{a^5b^3}}{\frac{1}{\sqrt{ab}}}$

Simplify,

$\sqrt{a^5b^3}*\sqrt{ab}$

Since both numbers are under a radical, one can rewrite them such that they are under the same radical,

$\sqrt{a^5b^3*ab}$

Simplify,

$\sqrt{a^6b^4}$

Since this operation is taking the square root, divide the exponents in half to do this operation:

$a^3b^2$

3

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$

Simplify, to simplify the expression in the numerator and the denominator, the base must be the same. Remember, the base is the number that is being raised to the exponent. One subtracts the exponent of the number in the denominator from the exponent of the like base in the numerator. This only works if all terms in both the numerator and the denominator have the operation of multiplication between them:

$(\frac{a^8}{b^-^4})^\frac{1}{4}$

Bring the negative exponent to the numerator. Change the sign of the exponent and rewrite it in the numerator,

$(a^8b^4)^\frac{1}{4}$

This expression to the power of the one forth. This is the same as taking the quartic root of the expression. Rewrite the expression with such,

$\sqrt[4]{a^8b^4}$

SImplify, divide the exponents by (4) to simulate taking the quartic root,

$a^2b$

4

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$

Using all of the rules mentioned above, simplify the fraction. The only operation happening between the numbers in both the numerator and the denominator is multiplication. Therefore, one can subtract the exponents of the terms with the like base. The term in the denomaintor can be rewritten in the numerator with its exponent times negative (1).

$(a^3^-^1b^(^-^6^*^(^-^1^)^))^\frac{1}{2}$

$(a^2b^6)^\frac{1}{2}$

Rewrite to the half-power as a square root,

$\sqrt{a^2b^6}$

Simplify, divide all of the exponents by (2),

$ab^3$

7 0

3 years ago

What is 24x - 3 =7 I need to know because im in Detention and im at scool

ycow [4]

Why would someone give you the answer if you are in detention? I will tell you the first step which is to get rid of the -3 by adding positive three to both sides of the equation. Then from there, you should know what to do! Pay attention in class, and stop giving your teacher trouble!

8 0

3 years ago

(20 points) <br><br><br> answer need ASAP:”)

Sergio [31]

Ayy you doing e2020:) Ok the answer would be B. 1/3

6 0

3 years ago