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algol13
3 years ago
10

Find the equation of the line passing through (1,3) and perpendicular to y=-4/3-2​

Mathematics
1 answer:
Effectus [21]3 years ago
3 0

Answer:

x=1

Step-by-step explanation:

Find the negative reciprocal of the slope of the original line and use the point-slope formula.

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Find the solutions of the quadratic equation -9c² +2 +3 = 0.
Tresset [83]

Given that,

An equation : -9c² +2c +3 = 0

To find,

Find the value of x.

Solution,

We have, -9c² +2c +3 = 0

We can solve it using the formula as follows :

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here, a = -9, b = 2 and c =3

Put the values,

c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69

So, the solution are -0.47 and 0.69.

8 0
3 years ago
Plot the zeros of this function:<br><br> f(x) = (x – 1)(x – 7).
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Answer:

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Step-by-step explanation:

The zeros of a function is where the function crosses the x-axis. The x-intercepts are the zeros of a function.

f(x) = (x - 1)(x - 7)

Let output equal to 0.

0 = (x - 1)(x - 7)

Set factors equal to 0.

x-1=0\\x=1

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The zeros of the function are x=1 and x=7.

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Answer:

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Answer:

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Step-by-step explanation:

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