3 years ago

Find the equation of the line passing through (1,3) and perpendicular to y=-4/3-2

Mathematics

1 answer:

Effectus [21]3 years ago

3 0

Answer:

x=1

Step-by-step explanation:

Find the negative reciprocal of the slope of the original line and use the point-slope formula.

You might be interested in

Sam’s business manufactures 5 times as many widgets as Mary does every hour but Sam needs to stop for a few minutes every hour a

natita [175]

Answer:
A) S=5M-3

Explanation:

6 0

3 years ago

3. x + 4y = 30 x - 2y = 0

kolbaska11 [484]

Answer:

Step-by-step explanation:

Given that:

x + 4y = 30

x - 2y = 0

Subtracting both equations:

6y = 30

y = 30/6

y = 5

Putting in above equation

x + 4(5) = 30

x + 20 = 30

x = 10

i hope it will help you

5 0

3 years ago

Evaluate it..........

trasher [3.6K]

Answer:

the answer is $\frac{1}{41} (23x-2ln(5sinx+4cosx))$

Step-by-step explanation:

$\int {\frac{3sinx+2cosx}{5sinx+4cosx} } \, dx$

here,

a=3, b=2, c=5, d=4

$M=\frac{ac+bd}{c^2+d^2 }=\frac{3*5+2*4}{5^2+4^2}=\frac{23}{41}$

$N=\frac{bc-ad}{c^2+d^2 }=\frac{2*5-3*4}{5^2+4^2}=\frac{-2}{41}$

$\int {\frac{3sinx+2cosx}{5sinx+4cosx} } \, dx=\int{\frac{\frac{23}{41}(5sinx+4cosx)-\frac{2}{41}(5cosx-4sinx) }{5sinx+4cosx} }\,dx$

$=\frac{23}{41}\int\, dx -\frac{2}{41} \int{\frac{5cosx-4sinx}{5sinx+4cosx} }\, dx$

$=\frac{1}{41} (23x-2ln(5sinx+4cosx))$

pls mark it as the brainliest

5 0

3 years ago

Simplify √20 x √3 x √18 Answers 6√10 5√10 6√30 5√30

astraxan [27]

Answer:

the correct answer is 5√30

Step-by-step explanation:

√20= 2√5

√3=√3

√18= 3√2

2√5 x √3 x 3√2= 5√30

4 0

3 years ago

Find the greatest common factor (GCF) of 80 and 70.A 7 B. 5 C. 8 D. 10

LenaWriter [7]

Answer:

d. 10

Hope this helps

6 0

3 years ago

Find the equation of the line passing through (1,3) and perpendicular to y=-4/3-2​

Find the equation of the line passing through (1,3) and perpendicular to y=-4/3-2