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3 years ago

Two lines, C and D, are represented by the equations given below:

Mathematics

2 answers:

Softa [21]3 years ago

7 0

Answer:

(4,14) because both lines pass through it.

Step-by-step explanation:

A "solution" to a system of equations is simply a point that both lines pass through.

First image is the solution found through graphing and the second image is the solution found through substitution.

telo118 [61]3 years ago

5 0

Two lines, C and D, are represented by the equations given below:

Line C: y = x + 10
Line D: y = 3x + 2

Which of the following shows the solution to the system of equations and explains why?

answer choices

(5, 17), because one of the lines passes through this point

(5, 17), because the point lies between the two axes

(4, 14), because the point does not lie on any axis

(4, 14), because both lines pass through this point

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What is the approximate length of the diameter, d? Use 3.14

Dimas [21]

Answer: 15.9

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

Does anyone know how to do this

dusya [7]

$\dfrac{\mathrm dy}{\mathrm dx}=(y+2)^2\sin\left(\dfrac xe\right)$

a. If $y=k$ , then $\frac{\mathrm dy}{\mathrm dx}=0$ , so

$0=(k+2)^2\sin\left(\dfrac xe\right)\implies (k+2)^2=0\implies k=-2$

b. When $x=w$ , we're told $y$ has a horizontal tangent, which has slope $\frac{\mathrm dy}{\mathrm dx}=0$ . So we have

$0=(y+2)^2\sin\left(\dfrac we\right)\implies\sin\left(\dfrac we\right)=0\implies\dfrac we=2n\pi\implies w=2ne\pi$

where $n$ is any integer, whose smallest positive value occurs for $n=1$ , giving $w=2e\pi$ .

c. The equation is separable:

$\dfrac{\mathrm dy}{(y+2)^2}=\sin\left(\dfrac xe\right)\,\mathrm dx$

Integrate both sides to get

$-\dfrac1{y+2}=-e\cos\left(\dfrac xe\right)+C$

$y=-1$ when $x=0$ , so we find

$-1=-e+C\implies C=e-1$

Then the particular solution to the DE is

$-\dfrac1{y+2}=-e\cos\left(\dfrac xe\right)+e-1\implies y=\dfrac1{e\left(\cos\left(\frac xe\right)-1\right)+1}-2$

5 0

3 years ago

Help me pleaseeeeeeeee

vredina [299]

The area of ABCD is 640 cm²

<h3>What is similarity in trapezoid?</h3>

In order for two trapezoids to be similar their corresponding sides must have the same ratio. Since the largest base length in the image is and the corresponding side is , the other base must also be times greater than the corresponding side.

Given:

EF= 5 cm

AB = 20cm

Area of EFGH = 40 sq cm

Now,

As both trapezoid are similar. So, their corresponding sides must have the same ratio

EF/ AB= BC/ FG= CD/ HG= HE/ DA

So,

area (EFGH) : area(ABCD) = (EF/ AB)²

40 : area(ABCD)= (5/ 20)²

40 : area(ABCD) = 1/16

area (ABCD) =640 cm²

Hence, Area of trapezoid ABCD = 640 cm²

Learn more about this concept here:

brainly.com/question/23602236

#SPJ1

6 0

2 years ago

Is this how you get the slope intercept form?

Komok [63]

Slope-intercept form : y = mx + b

3) y + 4 = x

So, you need to move 4 to the other side, so that y is by itself.

Subtract 4 from both sides.

y = x - 4

~Hope I helped!~

7 0

3 years ago

What is 338.7 rounded to 2 significant figures?

Artemon [7]

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3 years ago