Calculate the moment of 3kg and 20cm away from the pivot

Physics

1 answer:

Oksi-84 [34.3K]3 years ago

4 0

Answer:

5.88 Nm

Explanation:

Applying,

Moment(M) = Force(F)×perpendicular distance(d)

M = F×d.................... Equation 1

But,

F = mg.................. Equation 2

Where m = mass, g = acceleration due to gravity.

Substitute equation 2 into equation 1

M = mgd................. Equation 3

From the question,

Given: m = 3 kg, d = 20 cm = 0.2 m

Constant: g = 9.8 m/s²

Substitute these values into equation 3

M = 3×0.2×9.8

M = 5.88 Nm

You might be interested in

Mason lifts a box off the ground and places it in a car that is 0.50 meters high. If he applies a force of 8.0 newtons to lift t

gtnhenbr [62]

The equation for work is W=DxF
W being work
D being distance
F being force
That would make the equation
8x.5=4

5 0

4 years ago

Read 2 more answers

What is the largest meteoroid that has collided with this planet

Burka [1]

Chicxulub. It's the most famous cataclysm ever, the meteorite that probably snuffed out the dinosaurs (along with three-quarters of all life on Earth) when it smashed into our planet 65 million years ago. The crater it left behind is actually one of the youngest and most accessible in the solar system.

6 0

3 years ago

A 1.0-kg block moving to the right at speed 3.0 m/s collides with an identical block also moving to the right at a speed 1.0 m/s

____ [38]

Answer:

Speed of both blocks after collision is 2 m/s

Explanation:

It is given that,

Mass of both blocks, m₁ = m₂ = 1 kg

Velocity of first block, u₁ = 3 m/s

Velocity of other block, u₂ = 1 m/s

Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :

$m_1u_1+m_2u_2=(m_1+m_2)v$