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Leokris [45]
3 years ago
8

Calculate the moment of 3kg and 20cm away from the pivot​

Physics
1 answer:
Oksi-84 [34.3K]3 years ago
4 0

Answer:

5.88 Nm

Explanation:

Applying,

Moment(M) = Force(F)×perpendicular distance(d)

M = F×d.................... Equation 1

But,

F = mg.................. Equation 2

Where m = mass, g = acceleration due to gravity.

Substitute equation 2 into equation 1

M = mgd................. Equation 3

From the question,

Given: m = 3 kg, d = 20 cm = 0.2 m

Constant: g = 9.8 m/s²

Substitute these values into equation 3

M = 3×0.2×9.8

M = 5.88 Nm

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6 0
3 years ago
Compared to the thickness and density of the continental crust of South America, the oceanic crust of the Pacific floor is______
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