Answer:
The force applied on one wheel during braking = 6.8 lb
Explanation:
Area of the piston (A) = 0.4 
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) = 
⇒ P = 
⇒ P = 16 
This is the pressure inside the cylinder.
Let force applied on the brake pad = 
Area of the brake pad (
)= 1.7
Thus the pressure on the brake pad (
) = 
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P =
⇒ 16 =
⇒ = 16 ×
Put the value of we get
⇒ = 16 × 1.7
⇒ = 27.2 lb
This the total force applied during braking.
The force applied on one wheel = 
= 
= 6.8 lb
⇒ The force applied on one wheel during braking.
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The voltage across the other lamp is also 5 V.
In fact, when two resistances are connected in parallel, they are connected to the same points of the circuit. This also means that the potential difference across the two sides of the resistors is the same, therefore the voltage across the two lamps connected in parallel is 5 V for both.
Answer:
4306.8625 J or 344549/80J (fraction form)
Explanation:
kinetic energy= 
mv²
= 
×72.5×10.9²
= 4306.8625 J or 344549/80 J
