How is heat transferred through radiation?

When drawing up liquid into a micropipette, put the tip in the liquid at a Choose... degree angle, push the plunger to the Choos

tangare [24]

Answer:

Explanation:

This question seeks to test the knowledge of operating a micropipette.

When trying to draw a liquid from a container using a micropipette (tip), the micropipette should be held vertically straight at an angle of 90 degrees with the plunger pushed to the first resistance and then released.

When trying to dispense the drawn liquid into another container, the micropipette is held vertically straight at the same 90 degrees but the plunger is pushed to the second/last point of resistance. You keep pressing the plunger at the same degree and resistance until dispensing is done.

3 0

3 years ago

The molar mass of a gas

zlopas [31]

Doggo x infinity dependent on the temperature. And the mass of mole of the gas

3 0

3 years ago

Read 2 more answers

Please help... !!!!!!!

Scilla [17]

Answer:

1) C. The precise location of weather-related phenomena

2) C. It shows that the galaxies are moving farther away.

Explanation:

1) The global positioning system can be used in many ways, like in navigation, mapping and surveying the land. It is also used to observe the small changes taking place in the movement of objects on earth. They are usually used to study earthquakes.

2) When light from the galaxies is shifted towards the longer wavelengths, it is called red shift. When light shifts towards the shorter wavelengths, it is called blue shift. Big bang theory states how the primordial universe started expanding from a hot and dense singularity, in the process of evolution of the universe.

The universe is expanding always. Galaxies that are a part of the universe keep expanding and move farther away from each other. The galaxies that are very far off appear to move much faster than the nearby galaxies.

6 0

3 years ago

A 2-kg ball is thrown at a speed of ____, exhibits 25j of kinetic energy.

bogdanovich [222]

Answer:

A 2-kg ball is thrown at a speed of 5 m/s, exhibits 25 J of kinetic energy.

Explanation:

Given that,

The mass of a ball, m = 2 kg

Kinetic energy of the ball, K = 25 J

We need to find the speed of the ball. The formula for the kinetic energy is given by :

$K=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 25}{2}} \\\\v=5\ m/s$

So,

A 2-kg ball is thrown at a speed of 5 m/s, exhibits 25 J of kinetic energy.

3 0

3 years ago

A large fake cookie sliding on a horizontal surface is attached to one end of a horizontal spring with spring constant k = 375 N

spayn [35]

Answer:

The conservation of energy should be used to answer this question.

a)

At the position where the spring is unstretched, the elastic potential energy of the spring is zero.

$K_1 + U_1 - W_f = K_2 +U_2\\K_1 - W_f = U_2$

since $U_1$ and $K_2$ is equal to zero.

$W_f = F_fx\\\\U_2 = \frac{1}{2}kx^2\\\\19 - (10)x = \frac{1}{2}(375)x^2\\\\375x^2 + 20x - 38 = 0$

The roots of this quadratic equation can be solved by using discriminant.

$\Delta = b^2 - 4ac\\x_{1,2} = \frac{-b \pm \sqrt{\Delta}}{2a}$

$x_1 = -0.346\\x_2 = 0.292$

We should use the positive root, so

x = 0.292 m.

b)

We should use energy conservation between the point where the spring is momentarily at rest, and the point where the spring is unstretched.

$K_2 + U_2 - W_f = K_3 + U_3\\U_2 - W_f = K_3$

since the kinetic energy at point 2 and the potential energy at point 3 is equal to zero.

$\frac{1}{2}kx^2 - F_fx = K_3\\K_3 = 15.987 - 2.92 = 13.067 J$

Explanation:

In questions with springs, the important thing is to figure out the points where kinetic or potential energy terms would be zero. When the spring is unstretched, the elastic potential energy is zero. And when the spring is at rest, naturally the kinetic energy is equal to zero.

In part b) the cookie slides back to its original position, so the distance traveled, x, is equal to the distance in part a). The frictional force is constant in the system, so it is quite simple to solve part b) after solving part a).

8 0

3 years ago