Answer:
Which of the following expressions are written as conversion factors (can be multiple)?
a. 2.54cm/1 in
b. 100cm/1 m
c. 1cc=1mL
d. 1mi/5280 ft
e. 1 lb = 16 oz
Explanation:
Which of the following expressions are written as conversion factors (can be multiple)?
a. 2.54cm/1 in
b. 100cm/1 m
c. 1cc=1mL
d. 1mi/5280 ft
e. 1 lb = 16 oz
Answer:
The object has decreasing acceleration and decreasing velocity.
Answer:
gasoline zone P_net = 6860 Pa
Water zone P_net = 26460 Pa
Force direction is out of tank
Explanation:
The pressure is defined
P = F / A
F = P A
let's write Newton's equation of force
F_net = F_int - F_ext
P_net A = (P_int - P_ext) A
The P_ext is the atmospheric pressure
P_ext = P₀
the pressure inside is
gasoline zone
P_int = P₀ + ρ' g h'
water zone
P_int = P₀ + ρ' g h' + ρ_water h_water
we substitute
Zone with gasoline
P_net = ρ' g h'
P_net = 700 9.8 1
P_net = 6860 Pa
Water zone
P_net = rho’ g h’ + rho_water g h_water
P_net = 6860 + 1000 9.8 2
P_net = 26460 Pa
To find the explicit value of the force, divide by a specific area.
Force direction is out of tank
C. Forces cannot be quantified
Forces always act in pairs and are subject to change
Acceleration=change in velocity divided by change in time or
we are given that it goes from 5m/s to 15m/s
in this case,
and the change in time or
is 1 second because this change occurs over a period of 1 second
so the acceleration is
the acceleration is
