Answer:
Let ABC be the given isosceles triangle in which AB=AC=13cm. Draw AD perpendicular from A on BC
Let BC=2x cm. Then BD=DC=x cm
In △ABD, we have
AB
2
+AD
2
+BD
2
(By pythagoras theorem)
⇒13
2
=AD
2
+x
2
⇒AD=
13
2
−x
2
=
169−x
2
Now, Area =60cm
2
⇒
2
1
(BC×AD)=60⇒
2
1
{2x×
169−x
2
}=60
⇒x
169−x
2
=60⇒x
2
(169−x
2
)=3600
⇒(x
2
−144)(x
2
−25)=0⇒x
2
=144orx
2
=25
⇒x=12orx=5
Hence, Base 2x=24cm or 10cm
solution
1/3 = 20/60
2/5 = 24/60
3/10 = 18/60
1/4 = 15/60
The shortest is the wood piece with the length of 1/4 ft
Answer:
Step-by-step explanation:
hello :
y=2x²−12x+16
y = 2(x²-6x+9-9)+16
y = 2(x-3)²-18+16
y = 2(x-3)²-2.....vertex -form when the vertex is : <em>(3, -2)</em>
Answer:
See pictures attached
Step-by-step explanation:
The conjunction is given by the intersection of 2 inequalities
-5 < x (or x > -5)
that is the set of real number such that x greater than -5, graphically is represented by picture 1 attached (the parentheses means that -5 IS NOT included)
and the inequality
x ≤ 7
which is the set of real number such that x less than or equal to 7, represented in picture 2 attached (the bracket means that 7 IS included)
When we intersect the two sets we obtain
– 5 < x ≤ 7
that is the set of numbers x such that x is greater than -5 AND x less than or equals to 7, which graphically is represented in picture 3 attached.
Bc u gotta add 15 plus 9 and than divided them by 2 and it gives u 3:56