Answer:
I. Hijo, h = 10 años
II. Padre, P = 40 años
Step-by-step explanation:
- Sea la edad del padre P.
- Sea la edad del hijo h.
Traduciendo el problema verbal a una expresión algebraica, tenemos;
P = 4h .....ecuación 1.
P + 5 = 3(h + 5) ........ecuación 2.
Simplificando aún más, tenemos;
P + 5 = 3h + 15
P = 3h + 15 - 5
F = 3h + 10 ......ecuación 3.
Sustituyendo la ecuación 1 en la ecuación 3;
4h = 3h + 10
4h - 3h = 10
<em>h = 10 años </em>
A continuación, encontraríamos la edad del padre;
P = 4h
P = 4 * 10
<em>P = 40 años</em>
S.A = (2×area of base) + area of lateral faces
Area of lateral faces = area of base × height
Area of lateral faces = 19×4×8=608
S.A = (2×19×4)+608
=760
Answer:
True
Step-by-step explanation:
If a quadrilateral (with one set of parallel sides) is an isosceles trapezoid, its legs are congruent.
<span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span>=<span><span><span>2<span>c3</span></span><span>(<span>c+11</span>)</span></span><span>(<span>c+11</span><span>)</span></span></span></span>
