What are the two systems of equations for this graph?
1 answer:
You might be interested in
Answer:
C
Step-by-step explanation:
The general rule for the quadratic function is
Use the data from the table:
We get the system of three equations:
Subtract these equations:
From the first equation
Substitute it into the second equation:
So,
The quadratic function is
Since we are translating this graph one unit to the right, replace x with (x-1)
Note: If you are translating a graph to the left by k units, replace x with (x+k), and if by the right, replace x with (x-k)
After simplifying, we now have the following equation:
This is the new equation. Let me know if you need any clarifications, thanks!
Answer:
A) y = (x + 3)² + 4
B) y = (x - 3)² + 2
C) y = (x - 1)² - 5
Step-by-step explanation:
2 units UP means that the vertex will be shifted from (-3 , 2) to (-3, (2 + 2) or (-3, 4)
As the y = (x + 3)² will still be zero at x = -3, we just need to change the "+ 2" to
"+ 4" to shift the curve upward by 2
y = (x + 3)² + 4
When we want to shift the curve to the right, we want the vertex to move from (-3, 2) to (3, 2)
This means that the term in parenthesis must be zero with our desired x value
(3 + C)² = 0
3 + C = 0
C = -3
y = (x - 3)² + 2
4 units right and 7 units down mean that the vertex is desired at (1, -5)
(1 + C)² = 0
C = -1
y = (x - 1)² - 5
