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docker41 [41]
3 years ago
15

What are the two systems of equations for this graph?​

Mathematics
1 answer:
ANTONII [103]3 years ago
7 0
The system of equations to this graph is (1,1)
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Help!! !,<br>is it right or not ​
Dahasolnce [82]

Answer:

No

Step-by-step explanation:

The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number

3 0
2 years ago
Joey and Emily’s teacher gave them each a triangle divided into three parts a,b, and c which looked like the triangle shown belo
polet [3.4K]
We need the photo to answer the question
4 0
3 years ago
Find the quadratic function that fits the following data. which one function fits.
Oksana_A [137]

Answer:

C

Step-by-step explanation:

The general rule for the quadratic function is

y=ax^2+bx+c

Use the data from the table:

y(50)=130\Rightarrow 130=a\cdot 50^2+b\cdot 50+c\\ \\y(70)=130\Rightarrow 130=a\cdot 70^2+b\cdot 70+c\\ \\y(90)=200\Rightarrow 200=a\cdot 90^2+b\cdot 90+c

We get the system of three equations:

\left\{\begin{array}{l}2500a+50b+c=130\\ \\4900a+70b+c=130\\ \\8100a+90b+c=200\end{array}\right.

Subtract these equations:

\left\{\begin{array}{l}4900a+70b+c-2500a-50b-c=130-130\\ \\8100a+90b+c-2500a-50b-c=200-130\end{array}\right.\Rightarrow \left\{\begin{array}{l}2400a+20b=0\\ \\5600a+40b=70\end{array}\right.

From the first equation

b=-120a

Substitute it into the second equation:

5600a+40\cdot (-120a)=70\Rightarrow 800a=70,\\ \\ a=\dfrac{7}{80},\\ \\ b=-120\cdot \dfrac{7}{80}=-\dfrac{21}{2}=-10.5

So,

2500\cdot \dfrac{7}{80}+50\cdot (-10.5)+c=130\Rightarrow 218.75-525+c=130\\ \\c=130-218.75+525=436.25

The quadratic function is

y=\dfrac{7}{80}x^2-10.5x+436.25\\ \\y=0.0875x^2-10.5x+436.25

4 0
3 years ago
Write the equations after translating the graph of y = | 1/2x−2|+3, one unit to the right
AveGali [126]

y=|\dfrac{1}{2}x-2|+3

Since we are translating this graph one unit to the right, replace x with (x-1)

Note: If you are translating a graph to the left by k units, replace x with (x+k), and if by the right, replace x with (x-k)

y=|\dfrac{1}{2}(x-1)-2|+3

After simplifying, we now have the following equation:

=|\dfrac{1}{2}x-\dfrac{5}{2}|+3

This is the new equation. Let me know if you need any clarifications, thanks!

6 0
3 years ago
Read 2 more answers
Will mark brainliest IF you explain and solve
TEA [102]

Answer:

A) y = (x + 3)² + 4

B) y = (x - 3)² + 2

C) y = (x - 1)² - 5

Step-by-step explanation:

2 units UP means that the vertex will be shifted from (-3 , 2) to (-3, (2 + 2) or (-3, 4)

As the y = (x + 3)² will still be zero at x = -3, we just need to change the "+ 2" to

"+ 4" to shift the curve upward by 2

y = (x + 3)² + 4

When we want to shift the curve to the right, we want the vertex to move from (-3, 2) to (3, 2)

This means that the term in parenthesis must be zero with our desired x value

(3 + C)² = 0

3 + C = 0

C = -3

y = (x - 3)² + 2

4 units right and 7 units down mean that the vertex is desired at (1, -5)

(1 + C)² = 0

C = -1

y =  (x - 1)² - 5

4 0
3 years ago
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