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ladessa [460]
4 years ago
14

Which of the following is untrue concerning a reversible reaction?

Chemistry
1 answer:
Mars2501 [29]4 years ago
8 0

The statement that is untrue concerning a reversible reaction is The reaction always spends equal time in the forward and reverse direction. The answer is letter B. The reset of the statements are true concerning the reversible reaction.

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Which of the following has the smallest radius Rb+, K, K+, or Rb+
Stells [14]
The trend of elemental radius increases from top to bottom and from right to left. This means Rb is greater than K. Incorporating the positive charges, K+ is smaller than K and Rb+ is smaller than Rb. Thus, the trend in increasing order is K+,K,Rb+,Rb. 
5 0
4 years ago
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Help NEED THE ANSWER OR HELP PLEASE !!!!<br><br> 3. What is the mass of 8.0 cm3 of metal A?
Anna35 [415]

Answer:

now this area isn't my expertise so take this with a grain of salt but I believe its about 91125 g

Explanation:

8 cm is about 45g cube that and its 91125 g

6 0
3 years ago
Suppose a sodium hydroxide solution was standardized against pure solid primary standard grade KHP. If 0.4798 g of KHP required
Readme [11.4K]

Answer:

The NaOH solution has a molarity of 0.052 M

Explanation:

<u>Step 1:</u> Data given

Mass of KHP = 0.4798 grams

Volume of NaOH= 45.22 mL = 0.04522 L

Molar mass of NaOH = 40 g/mol

Molar mass of KHP = 204.22 g/mol

<u>Step 2</u>: Calculate moles of KHP

Moles KHP = mass KHP / Molar mass KHP

Moles KHP = 0.4798 grams / 204.22 g/mol

Moles KHP = 0.00235 moles

<u>Step 3</u>: Calculate moles of NaOH

KHP here acts as a mono-acid so, the number of moles of NaOH = number of moles KHP = 0.00235 moles

<u>Step 4: </u>Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume NaOH

Molarity NaOH = 0.00235 moles / 0.04522 L

Molarity NaOH = 0.052 M

The NaOH solution has a molarity of 0.052 M

6 0
4 years ago
A sample of water with a mass of 27.56g and an unknown temperature loses 2443 Joules. If the final temperature is found to be 62
mixer [17]

Answer:

41.3 °C

Explanation:

From the question given above, the following data were obtained:

Mass (M) of water = 27.56 g

Heat (Q) loss = 2443 J

Final temperature (T2) = 62.5 °C

Initial temperature (T1) =?

NOTE: The specific heat capacity (C) of water is 4.18 J/g°C

Thus, we can obtain the initial temperature of the water by using the following formula:

Q = MC(T2 – T1)

2443 = 27.56 × 4.18 (62.5 – T1)

2443 = 115.2008 (62.5 – T1)

Divide both side by 115.2008

2443 / 115.2008 = (62.5 – T1)

21.20645 = 62.5 – T1

Collect like terms

21.20645 – 62.5 = – T1

– 41.3 = – T1

Divide both side by – 1

– 41.3 /– 1= – T1 / –1

41.3 = T1

T1 = 41.3 °C

Thus, the initial temperature of the water was 41.3 °C

8 0
3 years ago
Use the information in the square to answer the questions about copper.
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