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kykrilka [37]
3 years ago
14

He standard reduction potentials of lithium metal and chlorine gas are as follows: reaction reduction potential (v) li+(aq)+e−→l

i(s) −3.04 cl2(g)+2e−→2cl−(aq) +1.36 in a galvanic cell, the two half-reactions combine to 2li(s)+cl2(g)→2li+(aq)+2cl−(aq) calculate the cell potential of this reaction under standard reaction conditions. express your answer with the appropriate units.
Chemistry
1 answer:
AURORKA [14]3 years ago
3 0

 2 Li(s)  +Cl₂→  2 Li⁺ (aq)  + 2Cl⁻ (aq)

The cell potential   of  the reaction above   is +4.40V

<em><u>calculation</u></em>

Cell  potential  =∈° red - ∈° oxidation

in  reaction above  Li  is  oxidized from oxidation state 0 to +1 therefore the∈° oxid = -3.04

  Cl  is  reduce   from oxidation  state 0 to -1 therefore  the ∈°red = +1.36 V

cell  potential is therefore = +1.36 v -- 3.04  = + 4.40 V

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