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oee [108]
4 years ago
8

Hich nuclide is most likely to undergo beta decay?which nuclide is most likely to undergo beta decay?co−52ar−35si−22mg−28

Chemistry
1 answer:
Setler [38]4 years ago
7 0
200
     Pt
 78
<span> is most likely to undergo beta decay.
</span>
<span>During the process of beta decay the mass number of the parent nuclide becomes equal to the newly created nuclide. On the other hand, the atomic number of the newly created nuclei increases or decreases by one unit.</span>
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Reactants on the left and products on the right
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What mass of TiCl4 must react with an excess of water to produce 50.0g of TiO2 if the reaction has a 78.9% yield
Kipish [7]

Answer:

\large \boxed{\text{150 g TiCl}_{4}}  

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:     189.68                  79.87

           TiCl₄ + 2H₂O ⟶ TiO₂ + 4HCl

m/g:                                 50.0

To solve this stoichiometry problem, you must

  • Convert the actual yield to the theoretical yield  
  • Use the molar mass of TiO₂ to convert the theoretical yield of TiO₂ to moles of TiO₂
  • Use the molar ratio to convert moles of TiO₂ to moles of TiCl₄
  • Use the molar mass of TiCl₄ to convert moles of TiCl₄ to mass of TiCt₄

1. Theoretical yield of TiO₂

\text{Theoretical yield} = \text{50.0 g actual} \times \dfrac{\text{100 g theoretical}}{\text{78.9 g actual}} = \text{63.37 g theoretical}

2.  Moles of TiO₂

\text{Mass of TiO}_{2} = \text{63.37 g TiO}_{2} \times \dfrac{\text{1 mol TiO}_{2}}{\text{79.87 g TiO}_{2} } = \text{0.7934 mol TiO}_{2}

3,  Moles of TiCl₄

The molar ratio is 1 mol TiO₂:1 mol TiCl₄.

\text{Moles of TiCl}_{4} = \text{0.7934 mol TiO}_{2} \times \dfrac{\text{1 mol TiCl}_{4}}{\text{1 mol TiO}_{2}} = \text{0.7934 mol TiCl}_{4}

4.  Mass of TiCl₄

\text{Mass of TiCl}_{4} = \text{0.7934 mol TiCl}_{4} \times \dfrac{\text{189.98 g TiCl}_{4}}{\text{1 mol TiCl}_{4}} =\textbf{150 g TiCl}_{\mathbf{4}} \\\\\text{You must use $\large \boxed{\textbf{150 g TiCl}_{\mathbf{4}}}$}

5 0
3 years ago
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Anastasy [175]

Answer:

1:C as all metal are good conductors of heat & electricity

2:D conductivity as it needs delocalized electrons normaly

3:B good conductors of heat & electricity

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What is the ROUNDED atomic number for this elements?
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Sodium/Atomic number

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Gold/Atomic number

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Potassium/Atomic number

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Silicon/Atomic number

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