B, Because the classroom started with cylinder cups they should add 7mL into the cup and then transfer the 7mL on the cups
Answer = 23.2146762081 pounds.
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13% of 81 = 10.53
10.53 converted to pounds (lbs) = 23.21......pounds
It doesn't exactly mean anything, but it does describe the second group of elements, the Alkali Earth Metals.
Answer:
<u>167.2 g</u>
Explanation:
Known
VC4H10 = 21.3
T = 0.00 C (convert to Kelvin: 273 K)
P = 1.00 atm
Unknown
m = ?g
1. <u>Write the balanced chemical equation</u>
1 C4H10 + 1O2 -----> 4 CO2 + 5 H2O
2. <u>Find the volume ratio of Carbon Dioxide to Butane </u>
1 C4H10 4 CO2 = 4 volumes CO2 / 1 volume C4H10
3.<u> Multiply by the known volume of n (butane)</u>
21.3 L C4H10 x 4 volumes CO2 / 1 volume C4H10 = 85.2 L C4H10
4. <u>Use ideal gas law</u>
PV = nRT solve for n ----> n = PV/RT
n= (1.00 atm) (85.2 L) / (0.0821 L atm/mol K) (273) = 3.80 mol CO2
5.<u> Find molar mass of CO2</u>
1 C x 12 + 2 O x 16 = 44.00
6. <u>Multiply the ideal gas law solution (3.80) by molar mass CO2 (44.00)</u>
3.80 mol CO2 x 44.00 g CO2
= 167.2 g CO2
Explanation:
The balanced equation of the reaction is given as;
Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)
1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?
From the reaction;
2 mol of HBr produces 1 mol of MgBr2
Converting to masses using;
Mass = Number of moles * Molar mass
Molar mass of HBr = 80.91 g/mol
Molar mass of MgBr2 = 184.113 g/mol
This means;
(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2
18.3g would produce x
161.82 = 184.113
18.3 = x
x = (184.113 * 18.3 ) / 161.82 = 20.8 g
2. How many moles of H2O will be produced from 18.3 grams of HBr?
Converting the mass to mol;
Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol
From the reaction;
2 mol of HBr produces 2 mol of H2O
0.226 mol would produce x
2 =2
0.226 = x
x = 0.226 * 2 / 2 = 0.226 mol
3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?
From the reaction;
2 mol of HBr reacts with 1 mol of Mg(OH)2
18.3g of HBr = 0.226 mol
2 = 1
0.226 = x
x = 0.226 * 1 /2
x = 0.113 mol