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algol [13]
3 years ago
12

In the circle below, QS is a diameter. Suppose m RS 134º and m ZSRT = 44º. Find the following.

Mathematics
1 answer:
I am Lyosha [343]3 years ago
5 0

Answer:

m<QRT=90 ° the inscribed angle from the diameter is 90

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Using this formula, how many sides does a polygon have if the sum of the interior angles is 1,260°? Round to the nearest whole n
nikdorinn [45]

Answer:

9 Sides

Step-by-step explanation:

According to the Question,

  • Given That, The sum of the interior angles(s), in an n-sided polygon can be determined using the formula s=180(n−2), where n is the number of sides

Therefore, The sides do a polygon have if the sum of the interior angles is 1,260°.

Put The Values in Formula, we get

1260=180(n−2)

n-2 = 7

n=9 (9 Sides)  

6 0
3 years ago
Denise wants to cover a 21.75 square foot wall with weathered wood. If each box of weathered wood contains 1.5 square feet of wo
natka813 [3]

Answer: 15 boxes

Step-by-step explanation:

From the question, we are informed that Denise wants to cover a 21.75 square foot wall with weathered wood and that each box of weathered wood contains 1.5 square feet of wood.

The number of boxes of weathered wood that she need will be calculated by dividing 21.75 square feet by 1.5 square feet. This will be:

= 21.75/1.5

= 14.5

= 15 boxes approximately

6 0
3 years ago
1 1/4 miles equals how many feet
Artist 52 [7]
I Hope This Helps ( Don't Forget To Add Me & Say Thank Youu ❤️ )

7 0
3 years ago
Which equation is equivalent to ry (3x +2y) = 4?
d1i1m1o1n [39]

Answer:

I pretty sure it's C or lllll

3 0
3 years ago
2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
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