C. (5, -11) hope this helps and I’m like sure sure it’s right
Slope = (y₂- y₁) / (x₂- x₁)
Points C( 3, -5) and D (6, 0) compare to (x₁, y₁) and (x₂, y₂)
Slope = (0 - -5) / (6- 3) = (0+5) / (3) = 5/3
Slope = 5/3
Equation of line given a slope and point, y - y₁ = m(x - x₁)
m = 5/3, let point C( 3, -5) = (x₁, y₁)
y - - 5 = (5/3) (x - 3)
y + 5 = (5/3)(x - 3)
3(y + 5) = 5(x - 3)
3y + 15 = 5x - 15
3y = 5x - 15 - 15
3y = 5x - 30
Hence the equation of the line is 3y = 5x - 30
Answer:
Solve the equation for x by finding a
, b
, and c of the quadratic then applying the quadratic formula.
Step-by-step explanation:
Exact Form:
x = -5±√
5/2
Decimal Form:
x = −
1.38196601
…
, −
3.61803398
…
She should have 4 cups of banana pudding left
Answer:
D. 20 quarts
Step-by-step explanation:
correct
