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3 years ago

Identify the range of the function shown in the graph

Mathematics

2 answers:

Alisiya [41]3 years ago

4 0

I think it is C

I hope this helps

allochka39001 [22]3 years ago

3 0

Answer: The answer is (C). $y\geq 0.$

Step-by-step explanation: We are given a graph in the figure and we are to identify the range of the graphed function from the given options.

We can see in the figure that the values of x are greater than or equal to 0 and the corresponding values of y are also greater then or equal to 0. Since we are talking about the range of the function, so we will consider the y-values.

Thus, the range of the function will be $y\geq 0.$

Thus, (C) is the correct option.

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Lena [83]

The answer is the second sentence

4 0

2 years ago

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

Learn more here:

brainly.com/question/2962546

4 0

3 years ago

The arch of a bridge forms the upper half of an ellipse. The arch is 6 meters above the 20-meter-wide river. Write an equation f

aksik [14]

Answer:

$\frac{x^2}{36} + \frac{y^2}{100} = 1$

Step-by-step explanation:

Required

The equation of the ellipse

This is calculated as:

$\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$

Where:

$b =6$ ---- height

$a = 0.5 * 20 =10$ --- width

So:

$\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$

$\frac{x^2}{6^2} + \frac{y^2}{10^2} = 1$

$\frac{x^2}{36} + \frac{y^2}{100} = 1$

3 0

3 years ago

Select from the drop-down menus to correctly complete the statement.

Dominik [7]

We are given the expression
5⁹ x 5³
We can solve this using the rule of exponents which is
a^n x a^m = a^(a + m)
Therefore, the answer is
to keep the base and add the exponents
5⁵⁺³ = 5⁸

4 0

3 years ago

Read 2 more answers

NEED HELP ASAP WILL MARK BRAINLIEST AND WILL PUT LOTS OF POINTS

Stella [2.4K]

Answer:

9 cups

Step-by-step explanation:

We can use ratios to solve

1/3 cup red 4 cups red

----------------- = -------------------

3/4 cup yellow x cups yellow

Using cross products

1/3 *x = 3/4 *4

1/3x = 3

Multiply each side by 3

1/3 x * 3 = 3 * 3

x = 9

6 0

3 years ago