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3 years ago

The simple interest on a sum of money for 2 years at 12% per annum is rupees 1380

Mathematics

1 answer:

julia-pushkina [17]3 years ago

4 0

Answer:

5750

710.7

Step-by-step explanation:

Simple interest = principal. * rate * time

Principal (p) = sum of money

1380 = p * 0.12 * 2

1380 = 0.24p

p = 1380 / 0.24

p = 5750 rupees.

The compound interest :

A = P(1 + r/n)^nt

A = final amount

n = number of compounding times per period

t = period

A = 5750(1 + 0.12/2)^2*1

A = 5750(1 + 0.06)^2

A = 5750(1.06)^2

A = 5750 * 1.1236

A = 6460.7

Hence, compound interest is :

Final amount - principal

6460.7 - 5750

= 710.7 rupees

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Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

3 years ago

Solve the system of equations for 7x+2y=16 and -21x-6y=24

Georgia [21]

Simplifying
7x + 2y = 16

Solving
7x + 2y = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.
7x + 2y + -2y = 16 + -2y

Combine like terms: 2y + -2y = 0
7x + 0 = 16 + -2y
7x = 16 + -2y

Divide each side by '7'.
x = 2.285714286 + -0.2857142857y

Simplifying
x = 2.285714286 + -0.2857142857y

6 0

3 years ago

(n 4 - 2n 3 - 3n 2 + 7n - 2) ÷ (n - 2)

GrogVix [38]

I believe it's

- 1 - $\frac{4}{n - 2}$

Hope I helped! ( Smiles )

7 0

3 years ago

Read 2 more answers

In a survey of 2,800 people who owned a certain type of car, 1,680 said they would buy that type of car again. What percent of

Paraphin [41]

Answer:

60% were satified and would buy the car again

Step-by-step explanation:

5 0

3 years ago

A company is paying a local television station to run its commercials. The cost for running commercials is a one-time campaign f

Margarita [4]

The y-intercept is the value of y when x is equal to zero. From the equation,

y = 500 + 50x

the y-intercept is calculated by:

y = 500 + 50(0) = 500

Therefore, the correct answer is option B. The y-intercept is 500; it represents the one-time campaign fee.

8 0

3 years ago