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3 years ago

What is the value of the expression below when x = -5 and y = -10 |3x - y| +4

Mathematics

1 answer:

Oksanka [162]3 years ago

7 0

Answer:

-1 is your answer for this mate

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A person can order a new car with a choice of 13 possible colors, with or without air conditioning, with or without automatic tr

Gnoma [55]

Answer:

208

Step-by-step explanation:

13 options for colours = 13C1 = 13

AND

2 options for A/C = 2C1 = 2

AND

2 options for transmission = 2C1 = 2

AND

2 options power windows = 2C1 = 2

AND

2 options for CD player = 2C1 = 2

So,

13×2×2×2×2 = 208

3 0

3 years ago

Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal

pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and $\frac{11}{6}$ .

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form $f(x) = 0$ based on the following formula:

$x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}$

Where:

$x_{i}$ - i-th Approximation, dimensionless.

$x_{i+1}$ - (i+1)-th Approximation, dimensionless.

$f(x_{i})$ - Function evaluated at i-th Approximation, dimensionless.

$f'(x_{i})$ - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be $f(x) = x^{2}-8$ and $f'(x) = 2\cdot x$ , the resultant expression is:

$x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}$

First iteration: ( $x_{1} = 2$ )

$x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}$

$x_{2} = 2 + \frac{4}{4}$

$x_{2} = 3$

Second iteration: ( $x_{2} = 3$ )

$x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}$

$x_{3} = 2 - \frac{1}{6}$

$x_{3} = \frac{11}{6}$

7 0

3 years ago

Can the gcf of a pair of numbers be greater than the pair itself

dlinn [17]

No. The GCF can't be bigger than either number.
(The LCM can).

7 0

3 years ago

A rectangle has a length of 25x to the power of 3 and a width of 5x of power of 2. Find the area in square units.

schepotkina [342]

C will be the answer

4 0

2 years ago

The box plots represent the distances run by the players in a football match.

Monica [59]

Answer:

Following are the response to the given question:

Step-by-step explanation:

Its scope, as well as the cross median range, could be established using the measurement for dispersal by looking at even a booth map. We simply search for the difference between the larger and lowest data value to define the range, and we make all the difference between the third quartile and first quarter for the disposing of products and services ranges.

Team A:

$R=V_{max} -V_{min} \to R= 10.2 – 8.8 = 1.4 \\\\IQR = Q_3 - Q_1 = IQR = 9.09 - 9.5 = 0.4\\\\$

Team B:

$R= 10.4 - 9.0 = 1.4\\\\IQR= 10.1 – 9.6 = 0.5$

Based on previous results, you see an equal range, but variation in the interquartile. Group B does have a greater confidence interval than Group A, therefore we can say it is far more consistent over group B distance. Group A is a different type.

7 0

2 years ago