Answer:
1. v₂ = 12.43 m/s
2. I₁ = - 80 N.s
3. I₂ = 80 N.s
Explanation:
Consider the following data given in the question:
m₁ = mass of the Cart 1 = 16 kg
m₂ = mass of the Cart 2 = 7 kg
u₁ = velocity of cart 1 before collision = 4 m/s
u₂ = velocity of cart 2 before collision = 1 m/s
v₁ = velocity of cart 1 after collision = - 1 m/s
v₂ = velocity of cart 2 after collision = ?
1.
Applying the law of conservation of momentum:
<u>v₂ = 12.43 m/s</u>
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2.
Impulse of cart 1 = I₁ = m₁(v₁ - u₁)
I₁ = (16 kg)(- 1 m/s - 4 m/s)
<u>I₁ = - 80 N.s</u>
<u></u>
3.
Impulse of cart 2 = I₂ = m₂(v₂ - u₂)
I₂ = (7 kg)(12.43 m/s - 1 m/s)
<u>I₂ = 80 N.s</u>
The formula used to find potential energy is <em>P.E. = M * G * H</em> (P.E. is potential energy, M is mass, G is gravitational pull, and H is height). So the answer to your question is <em>5 * 9.8 * 2</em>, which equals 98.
I just took the test and correct answer is D. inverted and smaller than the object.
Answer:
B and D
Explanation
Gravitational potential energy does not relate to graphs and it is about a moving object so b and d would not be correct