Answer:
A. D
B. χ2 > 3.841
C. χ2 = 3.4806
D. 0.0621
Step-by-step explanation:
Question A: The hypotheses the dean should use are:
a) H0 : π1 - π2 ≥ 0 versus H1 : π1 - π2 < 0.
b) H0 : π1 - π2 ≤ 0 versus H1 : π1 - π2 > 0.
c) H0 : π1 - π2 ≠ 0 versus H1 : π1 - π2 = 0.
d) H0 : π1 - π2 = 0 versus H1 : π1 - π2 ≠ 0.
Answer: (d)
H0 : π1 - π2 = 0 versus H1 : π1 - π2 ≠ 0.
(B). Referring to the scenario above, the null hypothesis will be rejected if the test statistic is ________.
Answer: χ2 > 3.841
(C). Referring to the scenario above, the value of the test statistic is ________.
Answer: χ2 = 3.4806 (using the formula)
(D). Referring to the scenario above, the p-value of the test is ________.
Answer: 0.0621 (the answer could be looked up, in table)
Answer: Ok so first 0.05(6000 - x) + 0.07x = 372
300 - 0.05x + 0.07x = 372
300 + 0.02x = 372
0.02x = 72
x = 3600
He invested $3600 at 7% and $2400 at 5%.
<h2>
Hope this helps have a bless day❤️</h2>
Step-by-step explanation:
F(x) = 2x + 3 i think would be the best way to write it
Answer:
Required Probability = 0.605
Step-by-step explanation:
Let Probability of people actually having predisposition, P(PD) = 0.03
Probability of people not having predisposition, P(PD') = 1 - 0.03 = 0.97
Let PR = event that result are positive
Probability that the test is positive when a person actually has the predisposition, P(PR/PD) = 0.99
Probability that the test is positive when a person actually does not have the predisposition, P(PR/PD') = 1 - 0.98 = 0.02
So, probability that a randomly selected person who tests positive for the predisposition by the test actually has the predisposition = P(PD/PR)
Using Bayes' Theorem to calculate above probability;
P(PD/PR) = 
= 
= 
= 0.605 .
Answer:
-245
Step-by-step explanation:
multiply 7 and -35 to get your answer.
I hope this helped <3
